We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be $2x$ .

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

$I=Prt$ , where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

$6\%=\frac{6}{100}=0.06$

$10\%=\frac{10}{100}=0.10$

Amount of interest earned from lower-yielding account: $2x(0.06)=0.12x$ .

Amount of interest earned from higher-yielding account: $x(0.10)=0.10x$ .

$0.12x+0.10x=6600$

Let us solve for x.

$0.22x=6600$

$\frac{0.22x}{0.22}=\frac{6600}{0.22}$

$x=30,000$

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be $2x\Rightarrow 2(30,000)=60,000$ .

Therefore, the man invested $60,000 at 6%.

8 0

3 years ago

(3,7) Quadrant where the point is located

AleksandrR [38]

Since both values are positive, it is in quadrant 1

6 0

3 years ago

Gabrielle's age is two times Mikhail's age. The sum of their ages is 81. What is Mikhail's age?

Darya [45]

Answer:

Step-by-step explanation:

Let g be Gabrielle's age and m be Mikhail's age.

We can turn the statements the problem gives us into mathematical expressions to help us solve.

Gabrielle's age is two times Mikhail's age:

g = 2m

The sum of their ages is 81:

g + m = 81

This gives us a system of equations that will allow us to solve for Gabrielle's age.

g + m = 81

(2m) + m = 81

3m = 81

m = $\frac{81}{3}$

m = 27

If we need to solve for Gabrielle's age, we can do the following.

g = 2m

2(27) = g

54 = g

g = 54

Mikhail's age is 27.

Gabrielle's age is 54.

8 0

3 years ago

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