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2 years ago

This is also 6th grade math. I would also like if you helped me on this question

Mathematics

2 answers:

puteri [66]2 years ago

5 0

1. Does not beat the record ( it ties with it so I doesn’t beat it)
2. It does Bc (w) is more that the record
3. It does NOT beat the record
4. It does beat the record

-BARSIC- [3]2 years ago

4 0

1: does not
2: it does
3: does not
4: it does

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There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val

polet [3.4K]

Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and total number of regular tickets.

So the equation can be written as;

$x+y=120\ \ \ \ \ equation\ 1$

Again,total amount is the sum of total number of premium tickets multiplied by cost of each premium ticket and total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

$99x+25y=5812\ \ \ \ equation\ 2$

Now We will multiply equation 1 by 25 we get;

$x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3$

Now Subtracting equation 3 from equation 2 we get;

$(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38$

We will now substitute the value of x in equation 1 we get;

$x+y=120\\38+y=120\\y=120-38\\y=82$

Hence There are 38 premium tickets and 82 regular tickets in a pile.

3 0

2 years ago

Which set of coefficients of the terms in the expansion of the binomial (x+y)^3 is correct ?

BigorU [14]

We are technically FOILing this out... with a power of 3.

(x+y)(x+y)(x+y)

So we can first factor out the first two "x+y"s.

$( x^{2} +2xy + y^{2} )$ , multiplied by the last "x+y".

$x^{3} +3 x^{2} y +3x y^{2} + y^{3}$

Coefficients are the number that comes in front of a variable.

In this case, 1 comes in front of $x^{3}$ , 3 comes in front of $x^{2} y$ , 3 comes in front of $x y^{2}$ , and 1 comes in front of $y^{3}$ .

Thus: 1, 3, 3, 1.
Answer Choice A

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2 years ago

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How many solutions does this system have?

Luden [163]

Answer:

One solution

Step-by-step explanation:

i grapghed it the lines do intersect at one point

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2 years ago

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NO is parallel to ML. How long is OL? 2/3ft 6ft 8ft 12ft

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Basic Proportionality Theorem: Basic Proportionality Theorem states that "If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio".

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