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3 years ago

A scientist is trying to identify an unknown cell. He determines that it has a nucleus and lysosomes.

Physics

2 answers:

Fittoniya [83]3 years ago

6 0

Answer:

Choice A) A Animal cell

Explanation:

kati45 [8]3 years ago

6 0

Answer:

Explanation:

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Martha must carry a 45 N package up three flights of stairs. Each flight of stairs has a height of 2.3m, and the actual distance

Darina [25.2K]

Answer:

310.5 J

Explanation:

The total work done by Martha is equal to the increase in gravitational potential energy of the package, which is equal to

$\Delta U = mg\Delta h$

where

(mg) = 45 N is the weight of the package

$\Delta h$ is the increase in height of the package

The package is carried up 3 flights of stairs, each one with a height of 2.3 m, so the total increase in heigth is

$\Delta h = 3 \cdot 2.3 m=6.9 m$

And so, the work done by Martha is

$U=(45 N)(6.9 m)=310.5 J$

3 0

4 years ago

What is the acceleration of a skier that goes from 2.50 m/s to 14.5 m/s while traveling 505 m down a slope?

Alik [6]

Answer:

493 m*m/s

Explanation:

14.5-2.50=12

505 x 12=493

3 0

3 years ago

Which of the following is a freshwater biome? A.wetland B.estuary C.ocean D.coral reef

Kaylis [27]

The answer is A wetland

8 0

3 years ago

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What trends were seen in Mendeleev’s periodic table?

katrin [286]

He arranged his periodic table by each elements atomic mass

3 0

3 years ago

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The 50-mm-diameter cylinder is made from Am 1004-T61 magnesium and is placed in the clamp when the temperature is T1 = 15°C. If

Sergio [31]

Answer:

The temperature of steel first becomes 12 MPa at a temperature of 18.65°C

Explanation:

Given that,

Diameter = 50 mm

Temperature = 15°C

Diameter = 10 mm

Stress = 12 MPa

We need to calculate the temperature of steel

Using formula of stress

$stress=\alpha Y\Delta T$

Where, Y = young modulus

T = temperature

$\alpha$ = coefficient of linear expansion of the material

Put the value into the formula

$12\times10^{6}=17.3\times10^{-6}\times190\times10^{9}\times(T_{2}-15)$

$(T_{2}-15)=\dfrac{12\times10^{6}}{17.3\times10^{-6}\times190\times10^{9}}$

$T_{2}=3.650+15$

$T_{2}=18.65^{\circ}$

We need to calculate the temperature of magnesium

Using formula of stress

$stress=\alpha Y\Delta T$

Put the value into the formula

$12\times10^{6}=25.2\times10^{-6}\times45\times10^{9}\times(T_{2}-15)$

$(T_{2}-15)=\dfrac{12\times10^{6}}{25.2\times10^{-6}\times45\times10^{9}}$

$T_{2}=10.5+15$

$T_{2}=25.58^{\circ}$

Hence, The temperature of steel first becomes 12 MPa at a temperature of 18.65°C

7 0

3 years ago