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3 years ago

Balance the equation by choosing the correct coefficient numbers in the drop down menus.

Physics

1 answer:

SpyIntel [72]3 years ago

7 0

Answer:

SO₂ + 2H₂ —> S + 2H₂O

The coefficients are: 1, 2, 1, 2

Explanation:

SO₂ + H₂ —> S + H₂O

The above equation can be balance as follow:

SO₂ + H₂ —> S + H₂O

There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:

SO₂ + H₂ —> S + 2H₂O

There are 2 atoms of H on the left side and 4 atoms the right side. It can be balance by writing 2 before H₂ as shown below:

SO₂ + 2H₂ —> S + 2H₂O

Now, the equation is balanced.

The coefficients are: 1, 2, 1, 2

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Answer:

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Explanation:

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3 years ago

The compass of an airplane indicates that it is headed due north and its airspeed indicator shows that it is moving through the

yarga [219]

Answer:

Airplane speed relative to the ground is 260 km/h and θ = 22.6º direction from north to east

Explanation:

This is a problem of vector composition, a very practical method is to decompose the vectors with respect to an xy reference system, perform the sum of each component and then with the Pythagorean theorem and trigonometry find the result.

Let's take the north direction with the Y axis and the east direction as the X axis

Vy = 240 km / h airplane

Vx = 100 Km / h wind

a) See the annex

Analytical calculation of the magnitude of the speed and direction of the aircraft

V² = Vx² + Vy²

V = √ (240² + 100²)

V = 260 km/h

Airplane speed relative to the ground is 260 km/h

Tan θ = Vy / Vx

tan θ = 100/240

θ = 22.6º

Direction from north to eastb

b) What direction should the pilot have so that the resulting northbound

Vo = 240 km/h airplane

Vox = Vo cos θ

Voy = Vo sin θ

Vx = 100 km / h wind

To travel north the speeds the x axis (East) must add zero

Vx -Vox = 0

Vx = Vox = Vo cos θ

100 = 240 cos θ

θ = cos⁻¹ (100/240)

θ = 65.7º

North to West Direction

The speed in that case would be

V² = Vx² + Vy²

To go north we must find Vy

Vy² = V² - Vx²

Vy = √( 240² - 100²)

Vy = 218.2 km / h

8 0

4 years ago

Explain the expression “light travels at a speed”.

Anestetic [448]

Some things travel faster than the speed of light

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3 years ago

An electron is moving through a magnetic field whose magnitude is 9.21 × 10^-4 T. The electron experiences only a magnetic force

Marysya12 [62]

Answer:

$\theta=10.60^{\circ}$

Explanation:

Given that,

Magnetic field, $B=9.21\times 10^{-4}\ T$

Acceleration of the electron, $a=2.3\times 10^{14}\ m/s^2$

Speed of electron, $v=7.69\times 10^{6}\ m/s$

The force due to this acceleration is balanced by the magnetic force as :

$ma=qvB\ sin\theta$

$sin\theta=\dfrac{ma}{qvB}$

$sin\theta=\dfrac{9.1\times 10^{-31}\times 2.3\times 10^{14}}{1.6\times 10^{-19}\times 7.69\times 10^{6}\times 9.21\times 10^{-4}}$

$\theta=10.60^{\circ}$

So, the angle between the electron's velocity and the magnetic field is 10.6 degrees. Hence, this is the required solution,

8 0

4 years ago