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zaharov [31]
3 years ago
15

In the elements square on the periodic table, the number with the greatest numerical value the

Physics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

Osmium

Explanation:

Because Osmium has the highest numberic value

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Answer:

It is the way you see someone or something

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dopasuj wartości pracy z ramki do przedstawionych sytuacji ,a nastepnie wyraż te prace w dżulach uwaga jedna wartośc pracy nie b
Eduardwww [97]

Answer:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Explanation:

Całą część pytania można znaleźć na poniższym schemacie.

Z diagramu załączonego poniżej; mamy

A - samolot lotniczy

B - dźwig

C - podnoszenie ciężarów

Wszyscy to wiemy ;

1kJ = 1000 J

1MJ = 1000000 J

Mamy cztery opcje; i.e 200 MJ, 800 kJ, 1.6 kJ  and 250 mJ

Z czterech opcji można wykluczyć 250 mJ, ponieważ jest to 0,25 J, co przedstawia bardzo niską energię w porównaniu z trzema warunkami pokazanymi na schemacie.

Więc:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Największą pracę wykona samolot. Jest tak, ponieważ ma bardzo dużą masę i bardzo dużą prędkość. W związku z tym istnieje potrzeba wytworzenia ogromnej ilości ciepła i energii.

Z drugiej strony żuraw może podnieść ładunek o wiele większy i przewyższa ciężar ciężaru, więc praca wykonywana przez dźwig musi być zdecydowanie większa niż praca ciężarka.

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3 years ago
Fan blades would be an analogy for which atomic model? Thomson's Bohr's electron cloud Dalton's
nata0808 [166]
The correct answer would be Electron Cloud 
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3 years ago
An object is placed on the axis of a converging mirror of focal length 200mm. The image produced is inverterd and has a magnific
sp2606 [1]

Answer:1.7 is the answer

Explanation:im smart

6 0
3 years ago
3. When 10^14 electrons are removed from a neutral metal sphere, the charge on the sphere
Umnica [9.8K]

Answer:

Β. 16 με

Explanation:

Data provided in the question

Number of electrons removed = 10^14

And, the charge on one electron = 1.6\times 10^ {-19C}

Based on the above information, the charged on the sphere is

Therefore when we remove the electrons

So, the equation would be

10^{14} \times 1.6 \times 10^{-19 C}

= 1.6 \times 10

Therefore the same amount of the positive charged would be developed

Hence, the correct option is B.

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