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3 years ago

1. What layer of the Earth is flowing, solid and plastic?

Physics

2 answers:

melisa1 [442]3 years ago

5 0

Answer:

The mantle

Explanation:

The mantle is a plastic solid of varying densities which allow convection currents to flow molten rock towards the earth's surface resulting in volcanic activity, tectonic plate movement, earthquakes, and movement of continents.

attashe74 [19]3 years ago

5 0

It is Mantle it’s the thickest layer.

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If the length of the ramp is 2m and the height of the ramp is 1m , what is the mechanical advantage?

slamgirl [31]

Answer:

Mechanical Advantage is 2

Explanation:

M.A = length of ramp / height of ramp

= 2/1

5 0

3 years ago

(a) What resonant frequency would you expect from blowing across the top of an empty soda bottle that is 18 cm deep, if you assu

V125BC [204]

Answer:

476.387 Hz

714.583 Hz

Explanation:

L = Length of tube

v = Speed of sound in air = 343 m/s

Frequency for a closed tube is given by

$f=\dfrac{v}{4L}\\\Rightarrow f=\dfrac{343}{4\times 0.18}\\\Rightarrow f=476.389\ Hz$

The frequency is 476.387 Hz

If it was one third full $L=0.18-\dfrac{1}{3}0.18$

$f=\dfrac{v}{4L}\\\Rightarrow f=\dfrac{343}{4\times (0.18-\dfrac{1}{3}0.18)}\\\Rightarrow f=714.583\ Hz$

The frequency is 714.583 Hz

5 0

2 years ago

a bee flies 25m north of the hive, then 10m east, 5m west and 10m south. how far north and east of the hive is it now?

krok68 [10]

(25m north) + (10m south) = 15m north

(10m east) + (5m west) = 5m east

So the bee is now 15m north and 5m east of the hive.

7 0

3 years ago

Read 2 more answers

Two charged concentric spherical shells have radii of 11.0 cm and 14.0 cm. The charge on the inner shell is 3.50 ✕ 10−8 C and th

Sergio039 [100]

Answer:

The magnitude of the electric field are $2.38\times10^{4}\ N/C$ and $1.09\times10^{4}\ N/C$

Explanation:

Given that,

Radius of inner shell = 11.0 cm

Radius of outer shell = 14.0 cm

Charge on inner shell $q_{inn}=3.50\times10^{-8}\ C$

Charge on outer shell $q_{out}=1.60\times10^{-8}\ C$

Suppose, at r = 11.5 cm and at r = 20.5 cm

We need to calculate the magnitude of the electric field at r = 11.5 cm

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Where, q = charge

k = constant

r = distance

Put the value into the formula

$E=\dfrac{9\times10^{9}\times3.50\times10^{-8}}{(11.5\times10^{-2})^2}$

$E=2.38\times10^{4}\ N/C$

The total charge enclosed by a radial distance 20.5 cm

The total charge is

$q=q_{inn}+q_{out}$

Put the value into the formula

$q=3.50\times10^{-8}+1.60\times10^{-8}$

$q=5.1\times10^{-8}\ C$

We need to calculate the magnitude of the electric field at r = 20.5 cm

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times5.1\times10^{-8}}{(20.5\times10^{-2})^2}$

$E=1.09\times10^{4}\ N/C$

Hence, The magnitude of the electric field are $2.38\times10^{4}\ N/C$ and $1.09\times10^{4}\ N/C$

7 0

3 years ago

A train takes ms eaddy 200 miles north and 150 miles south. The total trip took 3.5 hours what was the average velocity of the t

Verizon [17]

The whole point of this problem is to check how well you understand
the definitions of a few important quantities, like velocity, speed, distance,
displacement etc.

Before we begin, I just want to mention that 'MPG' is not a unit of either
velocity or speed, but I think I know what you mean.

-- For some reason, Ms. Eaddy rode 100 miles north on the train, then
stayed aboard while the train turned around and took her 150 miles south.
The total distance she rode was (100 + 150) = 250 miles. But she ended up
50 miles south of where she began.

-- Displacement for the whole trip = distance and direction from the start point
to the finish point.

Displacement = 50 miles south

-- Average velocity = (displacement) / (time)

50 miles south / 3.5 hours = <u>14.29 miles per hour south</u>

3 0

3 years ago