Question

ABC is a right triangle. If AC = 7 and BC 8, find AB. Leave your answer in simplest radical form.

Answer 1

Step-by-step explanation:

We don't know if AB is a hypotenuse or leg.

If AB is hypotenuse:

• $AB=\sqrt{AC^2+BC^2} =\sqrt{7^2+8^2} =\sqrt{49+64} =\sqrt{113}$

If AB is leg:

• $AB=\sqrt{BC^2-AC^2} =\sqrt{8^2-7^2} =\sqrt{64-49} =\sqrt{15}$

Answer 2

The answer is √113 units

The detailed answer is provided in the attached image.