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2 years ago

Write the unit fraction depicted in the model as a percent. One-fourth

Mathematics

1 answer:

yan [13]2 years ago

4 0

Answer:

1/4×100 = 0.25×100

= 25%

Thus,

1/4 = 25%

Step-by-step explanation:

Given the fraction

1/4

In order to write the fraction 1/4 as a percent, all we need is to multiply 1/4 by 100.

i.e.

1/4×100 = 0.25×100

= 25%

Therefore, we conclude that:

1/4 = 25%

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Llana [10]

9514 1404 393

Answer:

x = 12

Step-by-step explanation:

The similarity statement tells you corresponding sides have the same ratio.

AB/BC = FE/EC

x/10 = 6/5

x = 10(6/5)

x = 12

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2 years ago

Find the indefinite integral. (remember to use absolute values where appropriate. use c for the constant of integration.) x2 − 2

julsineya [31]

:) Well, I dunno about anyone else but this question makes my head spin!

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2 years ago

What is the slope for y=3x-4? What is the y-intercept for y=3x-4?

riadik2000 [5.3K]

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question the equation of the line is

y = 3x - 4

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Hope this helps you

3 0

2 years ago

36-9 divided [(0.24*5)+ (0.66*5)]

Ray Of Light [21]

[(0.24*5)+ (0.66*5)] == 4.50
0.24x5 = 1.20
0.66x5 = 3.30
+ ____
4.50

27.00÷4.5 = 0.166666667

4 0

2 years ago

Select the relations that are functions.

Arlecino [84]

Answer:

Depending on how the input of each function defined,

The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$ ,
The third choice $\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace$
The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

be defined for all elements in the domain, and
map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element $a$ from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be $\lbrace a,\, 6, \, C\rbrace$ . Similarly, the domain for the third and fourth relations should be $\lbrace 1,\, 2, \, 3\rbrace$ and $\lbrace a,\, b, \, c\rbrace$

8 0

2 years ago