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Brilliant_brown [7]
3 years ago
11

What are the solutions to the equation (x-6)(x+8)=0?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

x = 6, -8

Step-by-step explanation:

If (x - 6)(x + 8) = 0, that would imply that either (x - 6) or (x + 8) would equal zero. Using this, we can find that solving the two equations:

x - 6 = 0

and

x + 8 = 0

would yield the two solutions to the equation.

x - 6 = 0

Add 6 to both sides of the equation.

x = 6

So one of the solutions would be x = 6.

x + 8 = 0

Subtract 8 from both sides of the equation.

x = -8

So the other solution would be x = -8.

The two solutions are x = 6 and x = -8.

I hope you find my answer and explanation to be helpful. Happy studying.

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Answer:

The answer is 102 miles

Step-by-step explanation:

To get this, find either Hot Springs or Sturgis on the left hand column. Once you have found the row labelled with it, follow it over until the column with the   header of the other one. No matter which one you start with, you will get the same answer.

8 0
4 years ago
Write the equation of a line perpendicular to y=-12x+2 going through (0,-1)
DanielleElmas [232]

             \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

          <em>Write the equation of a line perpendicular to y=-12x+2 going </em>

<em>            through (0, -1)</em>

<em />

<em>      </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

        First, let's take a look at our provided information:-

  • A line \text{y=-12x+2}
  • A point (0, -1)
  • The line \text{y=-12x+2} is perpendicular to the line that goes through (0, -1)

     If two lines are perpendicular to each other, their slopes are opposite reciprocals of each other.

   So we take the slope of the given line, which is -12, change its sign from minus to plus:-

\Large\textit{12}

And now, We flip the number over:-

\Large\text{$\displaystyle\frac{1}{12}$}

Now that we've found the slope of the line, let's find its equation.

     The first step is to write it in point-slope form as follows:-

\longmapsto\sf{y-y_1=m(x-x_1)}

Replace letters with numbers,

\longmapsto\sf{y-(-1)=\displaystyle\frac{1}{12}(x-0)}

On simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} (x-0)}

On further simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} x}

Subtracting 1 on both sides,

\longmapsto\sf{y=\displaystyle\frac{1}{12} x-1}

\Uparrow\texttt{Our equation in slope-intercept form}

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

5 0
2 years ago
What is the slope of the linear function?
e-lub [12.9K]

Answer: Answer choice D

Step-by-step explanation: The linear function is y = -5/3 + 5, which means that the slope is 5/3. The fact that the slope is ascending to the left also eliminates the first two choices.

4 0
2 years ago
Read 2 more answers
What type of angle is created by the intersection of two perpendicular lines rats or line segment
zmey [24]

It should be a right angle (90º).

6 0
3 years ago
Write an equation for a circle with center at (5,-2) and diameter of 8 centimeters.
mars1129 [50]

Answer:

(x-5)^2+(y+2)^2=16

Step-by-step explanation:

lol brainlessly...

General Circle function: (x-h)^2+(y-k)^2=r^2, where h is the x-coordinate of the center, k is the y-coordinate of the center, and r is the radius.

The radius of the circle is half the diameter so: 8 / 2 = 4

The x-coordinate of the circle is 5

The y-coordinate of the circle is -2

Plug in.

(x-5)^2+(y-(-2))^2=4^2

(x-5)^2+(y+2)^2=16

5 0
3 years ago
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