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Lisa [10]
2 years ago
14

Does someone know the answer? Simplify it 3(2a^2-3a+1)-(2a+7)

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
7 0

Answer:

5a3-5a2

Step-by-step explanation:

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Marco needs to buy cat food. At the nearest store, 3 bags of cat food cost $15.75. How much would Marco spend on 5 bags of cat f
Ber [7]

Answer:

$29 dollars and 60 cents

Step-by-step explanation:

15.75 divided by 3 is 5.92 if rounded.

then 5.92x 5= 29.60

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3 years ago
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Beau buys a 3-pound bag of trail mix for a hike. He wants to make one-ounce bags for his friends with whom he is hiking. How man
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1 pound = 16 ounces

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Please help me do this question
bija089 [108]

Answer:

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3 years ago
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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
3 years ago
Dad is 4 times as old as his son Jim. In 10 years, dads age will be 20 years mare than twice jims age. How old is Jim?
luda_lava [24]
10 is the answer I’m AssuminG
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