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Lostsunrise [7]
2 years ago
5

what is the equation of the line that passes through (-2,-3) and is perpendicular to 2x-3y=6? ...?

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
4 0
The equation given in the question is

2x - 3y = 6
Dividing both sides of the equation by 3, we get
2/3 x - y = 2
y = 2/3 x - 2
Then, from the above equation we can tell that the slope of the line in the graph is 2/3. The slope of a line perpendicular to this slope will be - 3/2. The line also contains the points (-2,-3). 
Then, the equation of the perpendicular line will be
y = mx + b
- 3 = (- 3/2)(- 2) + b
- 3 = 3 + b
b = - 6
Then
y = (-3/2)x - 6
y + 6 = (- 3/2)x
2y + 12 = - 3x
3x + 2y = - 12
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Answer:

y=-3/5x+16

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m=(y2-y1)/(x2-x1)

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simplify

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Answer:

  r = 1/9

Step-by-step explanation:

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Since r is a constant, it will be the same for any corresponding pairs of x and y. It is convenient to choose both x and y as integers, as in the third table entry.

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<em>Additional comment</em>

It is not a bad idea to check to see that this works with other values of x and y. For the first line of the table, we have x = 11:

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Answer:

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