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Ksju [112]
2 years ago
10

Taylor is competing in a 30 kilometers race. She has already run 12.35 kilometers through a park and swam 3.75 kilometers. She w

ill bike the rest of the way.
How far does Taylor need to bike to finish the race?

a. 8.6 km

b. 13.9 km

c. 16.1 km

d. 17.65 km
Mathematics
1 answer:
miv72 [106K]2 years ago
7 0
B is the correct answer
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[[((3^3 - 7) • 5)/10] + ((1 + 3 + 6 + 9) - 10)]
Gekata [30.6K]

Answer: 19

Step-by-step explanation:

3^3=27, 27-7=20, 20·5=100, 100/10=10.

1+3=4, 4+6=10, 10+9=19, 19-10=9.

10+9=19.

7 0
3 years ago
Which postulate proves the two<br> triangles are congruent?
sammy [17]

Answer:

<em>AAS</em>

Step-by-step explanation:

<em>because</em><em> </em><em>here </em><em>it </em><em>is </em><em>given</em><em> </em><em>that </em><em>two </em><em>angle </em><em>are</em>

<em> </em><em>equal</em>

and a side is common between both traingle

so, both traingle are congruent by

<em><u>AAS</u></em>

hope it helps

5 0
2 years ago
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
Neporo4naja [7]
4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)

Used:\ (a-b)(a+b)=a^2-b^2
7 0
3 years ago
How many divisors of 63 are also divisors of 72? (Recall that divisors may be positive or negative.)
frutty [35]

1, 3, 9 and -1, -3, and -9 i guess

hope this helps

8 0
3 years ago
HELPPPPPPPPPPPPPPPPPPP PLEASEEEE
Softa [21]
So half of Nina's age is 10/2= 5. And since Greg is three years younger we subtract from 5 like so...
10/2=5
5-3
2
So Greg is 2 years old. I hope this helps love! :)

5 0
3 years ago
Read 2 more answers
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