Answer:
B.) 140 is your answer for your problem
M = 3rt^2 - 2rv
2rv = 3rt^2 - M
v = (3rt^2 - M)/2r
Log_10 100 is the same as 10 to the x power is 100
10^x=100
10^2=100
the answer is 2
Answer:
60 kilometers per hour (kmph) over the limit
Step-by-step explanation:
The speed limit is 60 kmph
Let's find his original rate:
We know D = RT
Where
D is the distance, in km
R is the rate, in kmph
T is the time in hours
He went 10 km in 5 minutes, so we need the time in hours, first. That would be:
5/60 = 1/12 hour
So, putting into formula, we find rate:
D = RT
10 = R(1/12)
R = 10/(1/12)
R = 10 * 12
R = 120 kmph
He was going over by:
120 - 60 = 60 kmph
Answer:

Step-by-step explanation:
We want to write the trignometric expression:

As an algebraic equation.
First, we can focus on the inner expression. Let θ equal the expression:

Take the secant of both sides:

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

By substitutition:

Using an double-angle identity:

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

Simplify. Therefore:
