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3 years ago

NEED ANSWER CORRECT NOW PLEASE !!! HELP !! WILL GIVE BRAINLIEST IMMEDIATELY !!

Mathematics

1 answer:

aleksley [76]3 years ago

4 0

Ill only answer the first 2 question since its only 6 points....

A. (21,3),(12,6)

B. -1/3

Work:
6-3/12-21
-3/9
-1/3

Hope this helps out

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What is the perimeter of the kite? a.44 b.140

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Answer:

B.) 140 is your answer for your problem

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2 years ago

M=3rt squared -2rv solve for v.

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M = 3rt^2 - 2rv
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3 years ago

What is Log 10 100 Or what can I do

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3 years ago

laurens suv was detected exceeding the posted speed limit of 60 kilometers per hour , how many kilometers would she have been tr

Vlada [557]

Answer:

60 kilometers per hour (kmph) over the limit

Step-by-step explanation:

The speed limit is 60 kmph

Let's find his original rate:

We know D = RT

Where

D is the distance, in km

R is the rate, in kmph

T is the time in hours

He went 10 km in 5 minutes, so we need the time in hours, first. That would be:

5/60 = 1/12 hour

So, putting into formula, we find rate:

D = RT

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R = 10/(1/12)

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6 0

2 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

2 years ago