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Answer:</h3><h3>
10 < x < 42</h3>
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Explanation:
Given a triangle with sides a and b, the third side c is bounded by this compound inequality
b-a < c < b+a
where a < b
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In this case, a = 16 and b = 26, so
b-a < c < b+a
26-16 < x < 26+16
10 < x < 42
I'm using a version of the triangle inequality theorem.
This unknown third side is between 10 cm and 42 cm. The third side cannot equal 10 nor can it equal 42.
Step-by-step explanation:
Please write complete question
What is the underlined word ??
the graph of 13y + kx = 4 and the line containing the points (5, -8) and (2, 4) are parallel.
We find the slope of parallel line using two given points
(5, -8) and (2, 4)
Slope formula is



so slope = -4
Slope of any two parallel lines are always equal
Lets find the slope of the equation 13y + kx = 4
Subtract kx on both sides
13 y = -kx + 4
Divide both sides by 13

Now slope = -k/13
We know slope of parallel lines are same
So the slope of 13y + kx = 4 is also -4
Hence we equation the slope and find out k

Multiply by 13 on both sides and divide by -1
k = 52
the value of k = 52