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zysi [14]
2 years ago
7

Why do we use a coeficient to remove the propotionality

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
5 0
Constant is the scale term in proportionality. Suppose one variable is dependent on the other and one variable become twice, other becomes also twice and if one becomes half, other too becomes half., but they are two different variables which are no-where linked (like cost(money) vs quantity). Quantity and cost are two different things but they abridge a mathematical relation of proportionality. So in the mathematics to abridge these two different variables, we need something. Constant serves that purpose.
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Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
3 years ago
Pls answer and explain how you got it - i will mark brainliest<br> (just answer #28)
Akimi4 [234]

Answer:

5 x^2 y^ (-3) z = ?

Step-by-step explanation:

We know the volume of a rectangular prism is given by

V = l*w*h

V = 2x^2 * y^-2 * ?

We are given the volume

V =10x^4 y^-5 z

Set  the two equal

10x^4 y^-5 z = 2x^2 * y^-2 * ?

Divide each side by 2x^2 y^-2

10x^4 y^-5 z /2x^2 y^-2 = 2x^2 * y^-2 * ?/2x^2 * y^-2

10x^4 y^-5 z/ 2x^2 y^-2 = ?

Simplifying

10/2  * x^4/x^2  y^-5/ y^-2  z = ?

We know that a^b/ a^c = a^(b-c)

5 x^ (4-2) y^(-5 - -2) z = ?

5 x^2 y^ (-5 +2) z = ?

5 x^2 y^ (-3) z = ?

4 0
3 years ago
Read 2 more answers
Find the value of an investment of $20,000 for 12 years at an annual interest rate of 3.85%
MatroZZZ [7]

Answer:

<h2> $31,745</h2>

Step-by-step explanation:

Compound continuously:

FVn = PV x e^rn

where

PV = $20,000

r = 3.85%

n = 12 years

plugin values into the formula:

FV₁₂ = $20,000 x e ⁰°⁰³⁸⁵ ⁽¹²⁾

FV₁₂ = $31,745

3 0
3 years ago
Suppose that in a normal half hour of practice, a tennis player expends 280 calories of energy.
sertanlavr [38]

Answer:

308 Calories

Step-by-step explanation:

So we start off with 280 as usual, but I will focus on the percent. The given percent is 110% "effort". What we would need to do here is, Firstly, change the percent into a decimal, and this is done by moving the decimal spot of 110%. What I mean is that 110.% and you move that little period over 2 times to the left and also remove the percent as for now because we will not need it. After that you would get 1.10. This is what we will multiply by. So if we did 280x1.10 it equals 308, and that is how I got 308

Hope this helps!

4 0
3 years ago
The reciprocal of a number plus the reciprocal of three times the number equals 1/3. find the number.
Aleksandr-060686 [28]
1/x + 1/3x = 1/3
3+1=x
x=4
6 0
2 years ago
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