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Volgvan
4 years ago
15

What is the prime factorization of 81m 2 x 3?

Mathematics
1 answer:
N76 [4]4 years ago
4 0
The answer to your question is <span>3^4 · m^2 · x^3 </span>
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Solve the problem 8.62 - 1/5
aliya0001 [1]
8.42 because 1/5 = 0.2
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3 years ago
Factor 2a2b3 - 14ab + 16a
zhuklara [117]

Answer:

2a(b^3 - 7b + 8)

Step-by-step explanation:

I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.

Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.

2a2b3 - 14ab + 16a

2(ab^3 - 7ab +8a)

2a(b^3 - 7b + 8)

6 0
3 years ago
2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.
shepuryov [24]

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
3 years ago
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Answer:

4

Step-by-step explanation:

  • To be perpendicular, the product of the slope is -1.
  • (x,y) Substituting the coordinates.
  • y= 1/3(x+3) + 1
  • y= 1/3x +2
5 0
2 years ago
Read 2 more answers
A metal rod is 3/4 meters long. It will be cut into pieces that are each 1/48 meters long. How many pieces will be made from the
Annette [7]
3/4=36/48 so 36 pieces can be made from the metal rod. Hope this helps!
8 0
3 years ago
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