Answer:
The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is 
⇒ C
Step-by-step explanation:
The formula of the slope of a line passes through points 
and 
is 
∵ The line passes through points (5 , 0) and (6 , -6)
∴ 
= 5 and 
= 6
∴ 
= 0 and 
= -6
Substitute these values in the formula of the slope
∵
∴ 
Let us look to the answer and find the same formula
The answer is:
The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is
50 because 50/100=2/4 and 2/4 is blue on the circle
If you want to see if they are equivalent just substitute any number such as 2, so 2.5(2) = 5 and 2 + 5 = 7, so they are not equivalent (THIS IS TRUE UNLESS YOU DIDNT PUT THE X VALUE IN THE QUESTION)
Answer:
1)b
2)d)80/360×36π≈25.12cm²
4)d)32.5
5)c)135°
6)d)4π/3
Step-by-step explanation:
1) because as we know
Circle equation
=(x-a)²+(y-b)²=r²
=(x-5)²+(y+1)²=36 (given)
=(x-(+5))²+(y-(-1))²=6²
So
C(5,-1)and r=6
2)as we know area of sector
=Theta/360×πr²
=80/360×6²π
80/360×36×3.14
80/10×3.14
=25.12
4)to figure out 4 we have to separate the shape into 2 parts
First semi-circul
Second rectangle
So the parameter of the shape
=Circumference of semi-circul + the parameter of the rectangle
=[10π×½+2(10+3.4)]-10 (as the dashed line is not a part of parameter)
=[15.7+26.8]-10
=32.5
5)3π/4
3×180/4
540/4
135
6)240°
240°×π/180°
4π/3
If xy=0 assume that at leas 1 is zero
set it to zero
0=2a^2-16a+32
undistribute 2
0=2(a^2-8a+16)
2*0=0 so assume
a^2-8a+16=0
factor
(a-4)(a-4)=0
set to zero
a-4=0
a=4
when a=4, equation equals zero
