According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
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Answer:
m = -3
Step-by-step explanation:
First, find two clear points:
(1, -2) (0, 1)
Then, use the slope formula:
m = <u>y2 - y1</u>
x2 - x1
m = <u>1 - (-2)</u>
0 - 1
= <u>3</u> = -3
-1
m = -3
This means that the rise-over-run is -3 over 1, or 3 over -1.
Which means three down and 1 to the right, or 3 up and 1 to the left.
Slope is the steepness of the line.
Answer:
The answer is 15
Step-by-step explanation:
I know and is not stupid
So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones

=

times

=

times

times

=

times 1 times 1=2/p
easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1
each member pays 2/p