All categories

3 years ago

I need help plz help

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

8 0

answer is C. 252 ft^2

split the figure into two pieces and first figure out the rectangle (shown in turquoise).

If you multiply the width and length (18*6) you should get 108.

Then figure out the trapezoid (in magenta). the formula is (a+b)/2*h where a and b are the bases and h is the height. the bases are given, 6 and 18. to find the height, subtract the entire figure's height by 6, which is 18-6 and gives us 12. so the formula converted to this problem is (6+18)/2*12. simplify parenthesis and get 24/2*12. 24/2=12, so multiply 12*12. The area of the trapezoid is 144. Add the areas of both figures together and get 252.

You might be interested in

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago

Express the fractions 1/2, 3/16, and 7/8 with an LCD

Ket [755]

<span>Least Common Denominator (LCD) is the least number which all the denominators can divide without remainder. The given denominators are 2, 16 and 8. The least number 2, 16 and 8 will divide without remainder is 16. Therefore, to express the fractions 1/2, 3/12, and 7/8 with an LCD, we multiply both the numerator and the denominator of each of the fractions with a common factor that makes the denominator to be 16. Therefore, 1/2, 3/16 and 7/8 expressed with an LCD are (1 x 8) / (2 x 8), 3/16, (7 x 2) / (8 x 2) = 8/16, 3/16, and 14/16.</span>

5 0

2 years ago

Help! please it is almost due

sesenic [268]

Answer:

H and F both intersect through M. its called the (mid point) or the zero ground of the shape. Its the exact middle meaning the lines go cross but it passes by the other line, that pass by is the middle..

Step-by-step explanation:

4 0

2 years ago

Helppppp. Pleaseee? :(

mylen [45]

There isnt enough information to solve the question, answer is E.

5 0

3 years ago

Read 2 more answers

Select the right answer multiple choice (HELPPP

murzikaleks [220]

Answer:

its C

Step-by-step explanation:

3 0

2 years ago