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4 years ago

What is 50000x700? and 100x123,478

Mathematics

2 answers:

notsponge [240]4 years ago

8 0

50000×700 equals 35000000
100×123478 equals 12347800

jok3333 [9.3K]4 years ago

7 0

The question given here has two parts and each part has to be answered separately. In case of both the multiplications, the answer might look to be huge but by applying a simple technique, anybody can do these multiplications without the help of any calculator.
Now let us take the case of first multiplication that is given:
50000 * 700
= 35000000
In this case all the zeroes present has to be written first and then 7 and 5 should be multiplied and put. This will get the answer easily.
Now we take the second multiplication given:
100 * 123478
= 12347800
In this case also the zeroes are simply put on the right side of the number 123478.

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A sine function has the following key features:

Frequency = 1/4π

Amplitude = 2

Midline: y = 2

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3 years ago

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Which simpler problems could be calculated to solve this problem?

Serggg [28]

Answer:

Option B

Step-by-step explanation:

We first need to calculate the total cost of all the four items then calculate the tip of the total cost. After this we add the tip to the cost of items and calculate change as follows.

Total cost of items

Cost of bottles =3*1.5=$4.5

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4 years ago

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What is the hight of a cylinder with a volume of 300 and a radius of 5 inches

Rashid [163]

Answer:

3.82 in

Step-by-step explanation:

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3 years ago

3.3^(2x+1)-103^x+1=0 need value of x

photoshop1234 [79]

Answer:

The value of $x$ is approximately -1.531.

Step-by-step explanation:

Let $3.3^{2\cdot x + 1}-103^{x+1} = 0$ , we proceed to solve this expression by algebraic means:

1) $3.3^{2\cdot x + 1}-103^{x+1} = 0$ Given

2) $3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0$ $a^{b}\cdot a^{c} = a^{b+c}$

3) $(3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0$ $(a^{b})^{c} = a^{b\cdot c}$

4) $(3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0$ $(a^{b})^{c} = a^{b\cdot c}$ /Commutative property

5) $\left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0$ Existence of multiplicative inverse/Definition of division/Modulative property/ $a^{b}\cdot a^{c} = a^{b+c}$

6) $\left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3}$ Existence of additive inverse/Modulative property/ $(a^{b})^{c} = a^{b\cdot c}$

7) $\log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3}$ Definition of logarithm.

8) $2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}$ $\log_{b} a^{c} = c\cdot \log_{b} a$

9) $2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3$ $\log_{b} \frac{a}{d}$

10) $x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3$ $\log_{b} a^{c} = c\cdot \log_{b} a$ /Associative property

11) $x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}$ Existence of multiplicative inverse/Definition of division/Modulative property

12) $x \approx -1.531$ Result

The value of $x$ is approximately -1.531.

4 0

3 years ago

Given: PRbisects ZQPS, PQ = 12units, and PS= 12units

Ganezh [65]

Answer:

Use SAS to show that triangles PRQ and PRS are congruent.

Step-by-step explanation:

Since PR bisects angle QPS, angles QPR and SPR are congruent. By reflexive property of congruence, PR is congruent to itself. Since PQ is congruent to PS, we can use SAS to show that the two triangles are congruent. By CPCTC, QR is congruent to SR.

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2 years ago