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Kisachek [45]
2 years ago
15

How to do the problem ​

Mathematics
2 answers:
charle [14.2K]2 years ago
7 0

Answer:

the answer is 10n-13

Step-by-step explanation:

this is a one step problem, all you need to do is add all the like terms together such as n and 9n and since they are both positives they add up to 10n and then with -10 and -3 they would add together to make -13. thats all there is to it, the answer is 10n-13

Anestetic [448]2 years ago
5 0

Answer:

Step-by-step explanation:

10n-13

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Help me my grade depends on this
taurus [48]

Answer:

If it’s asking what it is before the tax, it’s just $25.20.  With the tax, it’s $26.46

Step-by-step explanation:

3 0
1 year ago
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The grocery store is having a candy sale. Originally, a candy bar was $1.50. The
dangina [55]

The markdown rate is 66.7%.

<h3>Markdown rate</h3>

Using this formula

Markdown rate= Change in price/original price×100

Let plug in the formula

Markdown rate=$1.50-$0.50/$1.50

Markdown rate=$1.00/$1.50×100

Markdown rate=66.66%

Markdown rate=66.7% (Approximately)

Inconclusion the markdown rate is 66.7%.

Learn more about markdown rate here:brainly.com/question/1153322

8 0
2 years ago
What would be the function for this?
coldgirl [10]

Answer:

f(x) = 2x + 4

Step-by-step explanation:

This is an arithmetic sequence

y = a1 + (x - 1)d   where a1 = first term and d = common difference  so it is

y = 6 + (x - 1)*2

y = 2x  + 4    answer



7 0
3 years ago
A team of 17 softball players need to choose three players to refill the water cooler. How many different ways are there to sele
KATRIN_1 [288]
<h3>Answer: 680 different combinations</h3>

=======================================================

Explanation:

If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again.

So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible.

An alternative is to use the nCr formula with n = 17 and r = 3. That formula is

_n C _r = \frac{n!}{r!*(n-r)!}

where the exclamation marks indicate factorials

5 0
3 years ago
A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
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