The same as the diagonal of a square.
Hope this helped!
Answer:
11+6=17
Step-by-step explanation:
The given inequality holds for the open interval (2.97,3.03)
It is given that
f(x)=6x+7
cL=25
c=3
ε=0.18
We have,
|f(x)−L| = |6x+7−25|
= |6x−18|
= |6(x−3)|
= 6|x−3|
Now,
6|x−3| <0.18 then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03
the given inequality holds for the open interval (2.97,3.03)
For more information on inequality click on the link below:
brainly.com/question/11613554
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Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.
f(x)=6x+7,L=25,c=3,ϵ=0.18
.
<h2>
Answer:</h2>
The correlation that is shown in the scatter plot is:
Strong positive.
<h2>
Step-by-step explanation:</h2>
From the scatter plot we see that with the increase of one variable the second variable also increases.
Hence, the association is positive.
Also, if we draw a trend line that best represents the scatter plot then not all the points will lie above the line but all the data points are either over the line or very close to the line this means that the correlation coefficient is close to 1 but not exactly equal to 1.
Hence, the correlation is:
Strong positive.
( For perfect positive all the data points should lie above that line i.e. correlation coefficient must be equal to 1)

Hope you could get an idea from here.
Doubt clarification - use comment section.