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ra1l [238]
3 years ago
7

The solution set of a linear system whose augmented matrix is [a b c d] is the same as the solution set of Ax = d, where A = [a

b c]. Note: a, b, c, d are all column vectors.True/false
Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

True

Step-by-step explanation:

First statement

[a b c | d][x]

[a b c]x=d

ax+bx+cx=d

Second statement

Ax=d

Given that A = [a b c]

[a b c]x=d

ax+bx+cx=d

ax+bx+cx=d

Then, they are going to have the same solutions

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Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
abruzzese [7]

Answer:

There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.

Step-by-step explanation:

We have to make a hypothesis test to prove the claim that the average vertical jump of students differs from 15 inches.

The null and alternative hypothesis are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is 0.10.

The sample mean is 17 and the sample standard deviation is 5.37.

The degrees of freedom are df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-sided P-value for t=1.67 is P=0.11132.

This P-value is bigger than the significance level, so the effect is not significant. The null hypothesis can not be rejected.

There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.

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3 years ago
Angela has a vegetable garden that is shaped like a rectangle. The perimeter of Angelas vegetable garden is 64 feet. If the leng
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How do I solve this? <br>8(7+23)=8(7)+8()
rodikova [14]
USE PEMDAS
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PLEASE HELP ME, I HAVE NO IDEA! Find an equation for the line below.
irga5000 [103]

9514 1404 393

Answer:

  y -2 = -2/3(x +4)

Step-by-step explanation:

There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.

That form is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

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The two marked points are (-4, 2) and (5, -4). All we need is the slope.

The slope is given by the formula ...

  m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)

  m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3

Using the first point, the equation for the line can now be written as ...

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  y -2 = -2/3(x +4)

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