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Ratling [72]
3 years ago
7

Given f(x) = x - 7 and g(x) = x2. Find g(14))

Mathematics
2 answers:
Alex17521 [72]3 years ago
4 0

Answer:

196

Step-by-step explanation:

g(x) = x^2

Let x = 14

g(14)  = 14^2

        = 196

Free_Kalibri [48]3 years ago
4 0

Answer: 196

Step-by-step explanation:

F(x)= x-7

G(x)= x2

Find g(14)

G(x)= g(14)

Therefore x=14

Substitute for x in g(x)

G(14)= (14)^2

G(14)= 14×14

G(14)= 196

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I need to find the perimeter and area of the regular polygon.
mezya [45]
The area of a polygon is given by the formula Area = ap/2 where a is the length of the apothem and p is the perimeter. The apothem is a line from the center of the polygon perpendicular to a side.

Depending on the formula you know, you can find the length of a side in 1 of 2 ways. 

The first way uses a triangle. Using the radius of the polygon you can create 8 congruent triangles. The center angle will be 360 / 8 = 45 and two side lengths of 20. You can find the length of the base using the law of cosines.

c^2 = 20^2 + 20^2 - 2(20)(20)(cos 45)
c^2 = 400 + 400 - 800(cos 45)
c^2 = 800 - 800(cos 45)
c = sqrt(800 - 800(cos 45)
c = 15.31

The second way is to use this formula:
r = s / (2 sin(180 / n))
20 = s / (2 sin(180/8)
(20)(2)sin(22.5) = s
(40)sin(22.5) = s
s = 15.31

We need to calculate the perimeter. As there are 8 sides (8)(15.31) = 122.48
Now we need to calculate the apothem using

a = S / (2 tan (180 / n)
a = 15.31 / (2 tan (180 / 8))
a = 18.48

Now solve for the area

Area = ap/2
Area = (18.48)(122.48)/2
Area = 1131.72

perimeter = 122.48
area = 1131.72
7 0
3 years ago
Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In
Trava [24]

This is the complete question:

Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In the second assessment he scores 73%. After that, his scores keep increasing by 2% in every assessment.  Assume that x represents the number of assessments since he starts recording and y represents the scores in each assessment, which of the following describes the situation?

a. a relation only b.

b. neither a function nor a relation

c. a function only

d. both a relation and a function

Answer:

  • <u><em>d. both a relation and a function</em></u>

Step-by-step explanation:

<em>A relation</em> is any statement, either verbal or mathematical, that connects, interrelates or associates, two or more elements (objects, persons, variables).

The text describes a situation where the scores in the assesments are related to the number of statements since Mark starts recording, hence this is a relation.

<h2>Is this relation a function or not?</h2>

In order for a relation be a function, the association has to be unambiguos. This means that for a given input only one output can exist. If an input can have two or more outputs, then you can not determine which is the output for that input. This is what defines whether a relation is a function or not.

In the situation described in the text, x is the input, i.e. the number of assessments since Mark starts recording the scores. Definetely, the number of assessment is not repeated: there is only one first assessment, only one second assessment, only one third assessment, ... the number of assessment cannot not get repeated. Of course, if the input is not repeated, there is only one output associated to the input (each assessment has just one associated score)  and the relation is a function.

3 0
3 years ago
Let f(x) = x^2 − 5. Find f(-3)
Art [367]

Answer:

f(-3)=4

Step-by-step explanation:

Substitute x=-3 into the function

f(-3)=(-3)^2-5

f(-3)=9-5

f(-3)=4

5 0
2 years ago
Read 2 more answers
I think of a number, double it, and subtract two. I get nine.
solniwko [45]

Answer:

2(x) - 2 = 9 \\ 2x - 2 = 9 \\ 2x = 9 + 2 \\ 2x = 11 \\ x =  \frac{11}{2}  \\ x = 5 \frac{1}{2}

8 0
3 years ago
Read 2 more answers
Find the value of x. Round to the nearest tenth
levacccp [35]

Answer:

70.5

Step-by-step explanation:

Refer to attached image

8 0
3 years ago
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