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2 answers:
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Answer:
Step-by-step explanation:
<em>The </em><em>Remainder Theorem</em><em> states that when you divide a polynomial by a linear factor
, where
is a constant, the remainder is
evaluated at
</em>
<em>Moreover, according to the </em><em>Factor Theorem</em><em>, an extension of the Remainder Theorem, if the remainder of the function is </em><em>0</em><em> when evaluated at
, then
is said to be a factor of the polynomial
</em>
Given the 2 theorems above, it follows that if is a factor of
, then the remainder is equal to 0 when
is evaluated at
Which means
Third answer choice is correct.
Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
