With
in quadrant 3, we should expect both
and
to be negative, so that
is positive. The corresponding reciprocal expressions
will have the same sign.
![\cot\theta=\dfrac34\implies\tan\theta=\dfrac43](https://tex.z-dn.net/?f=%5Ccot%5Ctheta%3D%5Cdfrac34%5Cimplies%5Ctan%5Ctheta%3D%5Cdfrac43)
Recall that
, which means
![\sec\theta=-\sqrt{1+\tan^2\theta}=-\dfrac53](https://tex.z-dn.net/?f=%5Csec%5Ctheta%3D-%5Csqrt%7B1%2B%5Ctan%5E2%5Ctheta%7D%3D-%5Cdfrac53)
![\implies\cos\theta=-\dfrac35](https://tex.z-dn.net/?f=%5Cimplies%5Ccos%5Ctheta%3D-%5Cdfrac35)
Also recall that
, so
![\sin\theta=-\sqrt{1-\cos^2\theta}=-\dfrac45](https://tex.z-dn.net/?f=%5Csin%5Ctheta%3D-%5Csqrt%7B1-%5Ccos%5E2%5Ctheta%7D%3D-%5Cdfrac45)
![\implies\csc\theta=-\dfrac54](https://tex.z-dn.net/?f=%5Cimplies%5Ccsc%5Ctheta%3D-%5Cdfrac54)
Only the first two options are correct.
I think Jackyn is correct because 1/2 is half, which means it is .50. So 1/4 would be much smaller than .50 except if it was 2/4. The bigger the number is in negative, the smaller the number.
{0,3,5,8} ok this0 is the an0sw0er
Answer:
\/
Step-by-step explanation:
▪Picture 1. x = 28
![\frac{x}{42} = \frac{10 + x}{57} \\ 42(10 + x) = 57x \\ 420 + 42x = 57x \\ \frac{ \: \: \: \: \: \: \: \: \: \: \: - 42x = - 42x}{ \frac{420}{15} = \frac{15x}{15} } \\ \\ 28 = x](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B42%7D%20%20%3D%20%20%5Cfrac%7B10%20%2B%20x%7D%7B57%7D%20%5C%5C%2042%2810%20%2B%20x%29%20%3D%2057x%20%5C%5C%20420%20%2B%2042x%20%3D%2057x%20%5C%5C%20%20%5Cfrac%7B%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20-%2042x%20%3D%20%20-%2042x%7D%7B%20%5Cfrac%7B420%7D%7B15%7D%20%20%3D%20%20%5Cfrac%7B15x%7D%7B15%7D%20%7D%20%20%20%5C%5C%20%20%5C%5C%2028%20%3D%20x)
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▪Picture 2. I don't know what in trying to solve.
▪Picture 3.
•ABC = 50
•DEF = 95
•GHI = 65
•JKL = 55
▪Picture 4. I dont know how to do that
17+4 = 21 the answer is 21