I can't answer this question if we don't know by what scale the cylinder's radius was reduced. Luckily, I found the same problem that says the radius was reduced to 2/5. So, we find the ratio of both volumes.
V₁ = πr₁²h₁
V₂ = πr₂²h₂
where r₂ = 2/5*r₁ and h₂ = 4h₁
V₂/V₁ = π(2/5*r₁ )²(4h₁)/πr₁²h₁= 8/5 or 1.6
<em>Thus, the volume has increased more by 60%.</em>
Answer:
Step-by-step explanation:
Solve the inequality 5x − 4y > 20 for y, as follows: Subtract 5x from both sides, obtaining:
-4y > 20 - 5x;
Then divide all terms by -4:
y < -5 +(5/4)x, where the direction of the inequality sign has been reversed because of division by a negative quantity.
Temporarily replace the < symbol with = obtaining y = -5 +(5/4)x. Now choose at least three x values and find the corresponding y values. For example:
x y = -5 +(5/4)x
0 -5
4 0
-8 -15
Now plot these three points (0, -5), (4, 0) and (-8, -15). Draw a dashed line through them. Because of the < symbol in y < -5 +(5/4)x, shade the area underneath the dashed line.
-12 degrees.
Each hour, the temperature dropped by 3 degrees so it'd look like:
-3
-6
-9
-12
