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Kobotan [32]
3 years ago
7

If cotθ=3/4 and the terminal point determined by θ is in quadrant 3, then: (choose all that apply)

Mathematics
1 answer:
anygoal [31]3 years ago
6 0

With \theta in quadrant 3, we should expect both \cos\theta and \sin\theta to be negative, so that \tan\theta is positive. The corresponding reciprocal expressions (\sec\theta,\csc\theta,\cot\theta) will have the same sign.

\cot\theta=\dfrac34\implies\tan\theta=\dfrac43

Recall that 1+\tan^2\theta=\sec^2\theta, which means

\sec\theta=-\sqrt{1+\tan^2\theta}=-\dfrac53

\implies\cos\theta=-\dfrac35

Also recall that \cos^2\theta+\sin^2\theta=1, so

\sin\theta=-\sqrt{1-\cos^2\theta}=-\dfrac45

\implies\csc\theta=-\dfrac54

Only the first two options are correct.

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