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Schach [20]
3 years ago
6

Ecosystem services are services provided by

Chemistry
2 answers:
avanturin [10]3 years ago
5 0

Answer: nature that benefit mankind

Explanation:

Ecosystem services are the benefits that mankind freely gain from nature and well-functioning ecosystems. For example, agroecosystems, forest ecosystems, grassland ecosystems and aquatic ecosystems. When these ecosystems function well, they provide benefits such as agricultural produce, timber, and aquatic organisms such as fishes and crabs. These benefits together are called 'ecosystem services'.

Aleksandr-060686 [28]3 years ago
3 0

The answer is C) Communities in an effort to beautify local neighborhoods

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Does The nucleus of an atom contain all of the protons in the atom
insens350 [35]

Answer:

The nucleus, that dense central core of the atom, contains both protons and neutrons.

So to answer your question yes it does contain all of the protons in the atom.

* Hopefully this helps:) Mark me the brainliest:)!

5 0
4 years ago
PLS HURRY: 217 mL of Helium gas at 551oC is brought to standard temperature (0oC) while the pressure is held constant. What is t
krok68 [10]
71.9 mL is the answer
6 0
3 years ago
(LO 3N, 4G, 4O) Aluminum sulfate is also involved in dying fabrics. The gelatinous precipitate formed in the reaction with dilut
brilliants [131]

9.4 × 10⁻³ mg (0.73 mmoles) of Al(OH)₃ is formed

Explanation:

We have the following chemical reaction:

Al₂(SO₄)₃(aq) + 6 NaOH(aq) → 2 Al(OH)₃(s) + 3 Na₂SO₄(aq)

The precipitate mentioned by the problem is aluminium hydroxide Al(OH)₃.

Now to determine the number of moles of sodium hydroxide NaOH we use the following formula:

molar concentration =  number of moles / volume

number of moles = molar concentration × volume

number of moles of NaOH = 0.088 M × 25 mL = 2.2 mmoles

number of moles of Al₂(SO₄)₃ = 5.6 × 10⁻³ moles = 5.6 mmoles (found in the  problem text)

We see from the chemical reaction that 1 mole of Al₂(SO₄)₃ requires 6 moles of NaOH so 5.6 mmoles of Al₂(SO₄)₃ would require 6 times more NaOH which is 33.6 mmoles and we have only 2.2 mmoles. The limiting reactant will be NaOH.

Now we devise the following reasoning:

if        6 mmoles of NaOH produces 2 mmoles of Al(OH)₃

then  2.2 mmoles of NaOH produces X mmoles of Al(OH)₃

X = (2.2 × 2) / 6 = 0.73 mmoles of Al(OH)₃

mass of Al(OH)₃ = number of moles / molecular weight

mass of Al(OH)₃ = 0.73 / 78

mass of Al(OH)₃ =  9.4 × 10⁻³ mg

Learn more:

precipitation reaction

brainly.com/question/10400269

7 0
3 years ago
How many liters of 0.98 M have solution would react completely with 3.5 moles ca(oh)2
jasenka [17]

The question is typed wrong. Assuming the correct question is

How many liters of 0.98 M H2SO4 solution would react completely with 3.5 moles Ca(OH)2 ?

Answer:-

3.571 litres

Explanation:-

The balanced chemical equation for this reaction is

H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O

From the balanced chemical equation we see that

1 mole of Ca(OH)2 reacts with 1 mol of H2SO4.

∴3.5 moles of Ca(OH)2 reacts with 1 x 3.5 / 1 = 3.5 mol of H2SO4.

Strength of H2SO4 = 0.98 M

Volume of H2SO4 required = Number of moles of H2SO4 / Strength of H2SO4

= 3.5 moles / 0.98 M

= 3.571 litre

8 0
4 years ago
Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,
8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

6 0
3 years ago
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