Answer:
no. Because there is always that one person who doesn't want to
The answer is: 1.5 moles of oxygen are present.
V(O₂) = 33.6 L; volume of oxygen.
p(O₂) = 1.0 atm; pressure of oxygen.
T = 0°C; temperature.
Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).
At STP one mole of gas occupies 22.4 liters of volume.
n(O₂) = V(O₂) ÷ Vm.
n(O₂) = 33.6 L ÷ 22.4 L/mol.
n(O₂) = 1.50 mol; amount of oxygen.
Answer:
If
0.0357
mol
CaCl
2
is dissolved in water to make a
0.420
M
solution, what is the volume of the solution?
Answer:
1. K<10−3
Explanation:
Equilibrium Constant is an expression which involves the concentration of the product divided by the concentration of the reactant molecules.
However the concentration of the pure liquid and pure solid is regarded as 1.
Equilibrium expression for the equation 2H2(g)+O2(g)⇌2H2O(g)
Equilibrium Constant = [H2O]^2/[H2]^2 x [O2]
Since H2O is a pure liquid, its concentration = 1
There fore;
Equilibrium Constant = 1/[H2]^2 x [O2]
This shows that the Equilibrium Constant of the equation will be less than 1 and greater than 0.
