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KatRina [158]
4 years ago
13

How many liters of 0.98 M have solution would react completely with 3.5 moles ca(oh)2

Chemistry
1 answer:
jasenka [17]4 years ago
8 0

The question is typed wrong. Assuming the correct question is

How many liters of 0.98 M H2SO4 solution would react completely with 3.5 moles Ca(OH)2 ?

Answer:-

3.571 litres

Explanation:-

The balanced chemical equation for this reaction is

H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O

From the balanced chemical equation we see that

1 mole of Ca(OH)2 reacts with 1 mol of H2SO4.

∴3.5 moles of Ca(OH)2 reacts with 1 x 3.5 / 1 = 3.5 mol of H2SO4.

Strength of H2SO4 = 0.98 M

Volume of H2SO4 required = Number of moles of H2SO4 / Strength of H2SO4

= 3.5 moles / 0.98 M

= 3.571 litre

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Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should as
FrozenT [24]

Answer:

0.100 M AlCl₃

Explanation:

The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:

ΔT = W.i

Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.

i = final particles/initial particles

C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;

AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;

NaCl dissociates at Na⁺ and Cl⁻ so has 2 final particles and 1 initial particle, i = 2/1 = 2;

MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.

So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.

8 0
4 years ago
The current global population is 7.7 billion people, and the WHO estimates the minimum water need per person per day is 15 L. An
anygoal [31]

Answer:

a) The amount of freshwater available as groundwater, lakes and rivers, does not even reach one day the need for consumption for the current global population.  ( t = 5.489 E-13 day )

b) The annual terrestrial precipitation, reaches to sustain the drinking water needs for the current global population

Explanation:

Let P = 7.7 billion people = 7.7 E12 person

∴ water needed for the total population for one day:

⇒ water amount  = 7.7 E12 person * ( 15 L / person. day ) = 1.155 E14 L H2O /day

⇒ water amount = 1.155 E14 L H2O/day * 1 E1 Km² H2O / L H2O = 1.155 E15 Km² H2O/day * ( 365 day / year ) = 4.216 E17 Km²/year

∴ freshwater available:

freshwater = 6.34 E2 Km² H2O

how long will this water sustain the current population?

⇒ t = 6.34 E2 Km² * day / 1.155 E15 Km² = 5.489 E-13 day

this amount of freshwater does not even meet the need of the current global population.

∴ the annual terrestrial precipitation (Py) = 505000 Km³/year..........from literature

⇒ Py = 505000 Km³ H2O/year * ( 1000 m/Km )³ * ( 1000L/m³ )

⇒ Py = 5.05 E17 L H2O/year * ( 1 E1 Km² / L ) = 5.05 E18 Km² H2O/year

⇒ Py > water amount

the annual terrestrial precipitation of water, reaches to sustain the drinking water needs.

4 0
3 years ago
If 42.8 mL of 0.204 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solut
Aneli [31]

Hey There!

At neutralisation moles of H⁺ from HCl  = moles of OH⁻ from Ca(OH)2  so :

0.204 * 42.8 / 1000  => 0.0087312 moles

Moles of Ca(OH)2 :

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

0.0087312 / 2 => 0.0043656 moles (  since each Ca(OH)2 ives 2 OH⁻ ions )

Therefore:

Molar mass Ca(OH)2 = 74.1 g/mol

mass = moles of Ca(OH)2 * molar mass

mass =  0.0043656 * 74.1

mass = 0.32 g of Ca(OH)2


Hope that helps!

6 0
4 years ago
A compound is 40.0 % C, 53.3 % 0, and 6.66 % H What is its molecular formula if its molecular mass is 60 g? Show all your work
Ksenya-84 [330]
The molecular mass 58%
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inysia [295]

Answer:

Relief is one element on a topographic map

Explanation:

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