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2 years ago

I anm definitely not a halogen. But if all you knew about me

Chemistry

1 answer:

Dmitriy789 [7]2 years ago

5 0

The periodic law is a law relating the properties of the element with their

atomic numbers.

The element is potassium, K.

Reason:

By atomic mass, potassium is 39.10 g, while argon is 39.10 g.

Going by the atomic mass alone, potassium should come before argon in

the periodic table and therefore should be an halogen and not an alkali

metal.

However, the number of protons in the potassium is 19, and therefore larger

than the number of protons in argon, which is argon.

Therefore, the element is potassium, K.

Learn more about the periodic law here:

brainly.com/question/2207821

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Two important ways that energy is transported in the world around us is through

Ann [662]

Explanation:

The two ways that energy can be transferred are by doing work and by heat transfer.

5 0

3 years ago

4 NH3 + 6 NO → 5 N2 + 6 H2O How many moles of NH3 are necessary to produce 0.824 mol N2?

GrogVix [38]

4 mol NH₃ → 5 mol N₂
x mol NH₃ → 0.824 mol N₂

x=0.824*4/5=0.6592 mol

6 0

3 years ago

Chemistry! Help! Please!! Thanks

Vladimir79 [104]

Answers:

1. 3-ethyl-3-methylheptane; 2. 2,2,3,3-tetramethylpentane; 3. hexa-2,4-diene.

Explanation:

Structure 1

Identify and name the longest continuous chain of carbon atoms (the main chain has 7 C; ∴ base name = heptane).
Identify and name all the substituents [a 1C substituent (methyl) and a 2C substituent (methyl).
Number the main chain from the end closest to a substituent.
Identify the substituents by the number of the C atom on the main chain. Use hyphens between letters and numbers (3-methyl, 3-ethyl).
Put the names of the substituents in alphabetical order in front of the base name with no spaces (3-ethyl-3-methylheptane)

Structure 2

5C. Base name = pentane
Four methyl groups.
Number from the left-hand end.
If there is more than one substituent of the same type, identify each substituent by its locating number and use a multiplying prefix to show the number of each substituent. Use commas between numbers (2,2,3,3-tetramethyl).
The name is 2,2,3,3-tetramethylpentane.

Structure 3

Identify and name the longest continuous chain of carbon atoms that passes through as many double bonds as possible. Drop the -ne ending of the alkane to get the root name hexa-.
(No substituents).
Number the main chain from the end closest to a double bond.
If there is more than one double bond use a multiplying prefix to indicate the number of double bonds (two double bonds = diene) and use the smaller of the two numbers of the C=C atoms as the double bond locators (2,4-diene)
Put the functional group name at the end of the root name (hexa-2,4-diene).

Note: The name 2,4-hexadiene is acceptable, but the Preferred IUPAC Name puts the locating numbers as close as possible in front of the groups they locate.

7 0

3 years ago

Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c

KiRa [710]

Answer:

[Cl⁻] = 0.016M

Explanation:

First of all, we determine the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)

This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps

Initial x

React s

Eq x - s s 2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

Kps = s . (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s = ∛(1.7ₓ10⁻⁵ . 1/4)

s = 0.016 M

3 0

3 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

solong [7]

Answer:

$89.55~\%~of~Fe_2O_3~in~the~sample$

Explanation:

The first step in this reaction is the converstion from Kg of $Fe$ to grams of $Fe_2O_3$ .

$1.19x10^3~Kg~Fe~\frac{1000g~Fe}{1~Kg~Fe}~\frac{1~mol~Fe}{55.84~g~Fe}~\frac{1~mol~Fe_2O_3}{2~mol~Fe}~\frac{159.68~g~Fe_2O_3}{1~mol~Fe_2O_3}~\frac{1~Kg~Fe_2O_3}{1000~g~Fe_2O_3}$

$X~=~1.7x10^3~Kg~Fe_2O_3$

Then we can calculate the percentage of $Fe_2O_3$ in the sample:

$\%~Fe_2O_3~=~\frac{1.7x10^3~Kg~Fe_2O_3}{1.9x10^3~Kg~Sample}*100$

$89.55~\%~of~Fe_2O_3~in~the~sample$

3 0

3 years ago