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2 years ago

I anm definitely not a halogen. But if all you knew about me

Chemistry

1 answer:

Dmitriy789 [7]2 years ago

5 0

The periodic law is a law relating the properties of the element with their

atomic numbers.

The element is potassium, K.

Reason:

By atomic mass, potassium is 39.10 g, while argon is 39.10 g.

Going by the atomic mass alone, potassium should come before argon in

the periodic table and therefore should be an halogen and not an alkali

metal.

However, the number of protons in the potassium is 19, and therefore larger

than the number of protons in argon, which is argon.

Therefore, the element is potassium, K.

Learn more about the periodic law here:

brainly.com/question/2207821

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the 89.5kg boulder begins rolling down the 35.2m hill with a speed of 5.43m/s. Calculate the kinetic energy

galben [10]

<h3>Answer;</h3>

 = 1319.45 Joules 

<h3>Explanation;</h3>

Kinetic energy is the energy possessed by a body in motion;

It is given by the formula; 1/2mv², where m is the mass of the body and v is the velocity.

mass = 89.5 kg and v =5.43 m/s

Therefore;

Kinetic energy = 1/2 × 89.5 × 5.43 ²

 = 1319.45 Joules 

8 0

4 years ago

For a solution equimolar in HCN and NaCN, which statement is false? a. [H+] is larger than it would be if only the HCN were in s

balandron [24]

Answer:

option (d) is false.

Explanation:

Acid dissociation equilibrium of HCN is represented as-

$HCN\rightleftharpoons H^{+}+CN^{-}$

Acid dissociation constant, $K_{a}$ , is represented as-

$K_{a}=\frac{[H^{+}][CN^{-}]}{[HCN]}$

where species inside third bracket represents equilibrium concentrations of respective species

So, evidently, presence of excess $CN^{-}$ (or NaCN) in solution will combine with $H^{+}$ to produce HCN. Hence $H^{+}$ will be larger that it would be if only the HCN solution were present.

According to Le-chatlier principle, addition of HCN will shift equilibrium towards right and addition of NaCN will shift equilibrium towards left to keep constant $K_{a}$ value at a particular temperature.

NaOH gives acid-base reaction with HCN to produce NaCN and water. So, addition of NaOH will increase concentration of $CN^{-}$ and decrease concentration of HCN

6 0

3 years ago

1. How many moles of calcium are in 525g Ca?

Novosadov [1.4K]

Answer:

13.1743

Explanation:

1 grams Calcium to mol = 0.02495 mol

6 0

3 years ago

How can human use of natural resources pollute the environment? :(

gladu [14]

Answer:

If a human does an non ecofriendly thing such as litering, it can damage earths atmosphere

Explanation:

i duno

8 0

3 years ago

Read 2 more answers

What is the reaction corresponding to the standard enthalpy of formation of K2SO3(s)?

nalin [4]

Answer:

2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s)

Explanation:

The standard enthalpy of formation of a substance is the change in enthalpy that happens when one mole of the substance is formed from the elements in their standard states.

Thus, to calculate the standard state of formation of a compound you must:

1. Identify the elements that form the compound
2. Identify the standard form of each element
3. Set the equation to form one mole of the compound, which may require to use fractional coefficients for some of the elements.

Applying that to our compound K₂SO₃

1. Elements:

potassium, K;
sulfur, S; and
oxygen, O.

2. Standard forms of the elements:

potassium: solid, K(s)
sulfur: solid, octatomic molecules, S₈ (s)
oxygen: diatomic gas, O₂(g)

3. Reaction:

K(s) + S₈ (s) + O₂(g) → K₂SO₃ (s)

Balance, keeping one mole of K₂SO₃. You will need to use fractional coefficients for some elements:

2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s) ← answer

8 0

3 years ago