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1 year ago

I anm definitely not a halogen. But if all you knew about me

Chemistry

1 answer:

Dmitriy789 [7]1 year ago

5 0

The periodic law is a law relating the properties of the element with their

atomic numbers.

The element is <u>potassium, K</u>.

Reason:

By atomic mass, potassium is 39.10 g, while argon is 39.10 g.

Going by the atomic mass alone, potassium should come before argon in

the periodic table and therefore should be an halogen and not an alkali

metal.

However, the number of protons in the potassium is 19, and therefore larger

than the number of protons in argon, which is argon.

Therefore, the element is <u>potassium, K</u>.

Learn more about the periodic law here:

brainly.com/question/2207821

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Explain what would happen in Step 2 if the cylinder were heated with the plunger held steady.

Svetradugi [14.3K]

Answer:

be more descriptive

Explanation:

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3 years ago

Consider the chemical equation below. Upper M g (upper O upper H) subscript 2 plus 2 upper H upper N upper O subscript 3 right a

masha68 [24]

Answer:

Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O.

Explanation:

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3 years ago

Read 2 more answers

Which of the following is not a possible termination step in the free radical chlorination of methane? Group of answer choices ∙

vagabundo [1.1K]

Answer: first option is not a termination

∙CH3 + Cl2 → CH3Cl + Cl∙

Explanation:

Since a radical is formed as part of the product it means it's a propagation step and not a termination step, at termination no free radical exist as product

7 0

3 years ago

You drop an unknown substance that weighs 8.3g into a graduated cylinder with 6ml of water. The water rises to 8ml when you drop

valkas [14]

Answer:

<h3>The answer is 4.15 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of object = 8.3 g

volume = final volume of water - initial volume of water

volume = 8 - 6 = 2 mL

So we have

$density = \frac{8.3}{2} \\$

We have the final answer as

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7 0

3 years ago

By titration, it is found that 31.7 mL of 0.145 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentrati

arlik [135]

Answer:

0.184 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above, the following data were obtained:

Mole ratio of the acid, HCl (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This includes:

Volume of the base, NaOH (Vb) = 31.7 mL Molarity of the base, NaOH (Mb) = 0.145 M

Volume of the acid, HCl (Va) = 25.0 mL

Molarity of the acid, HCl (Ma) =?

Finally, we shall determine the molarity of the acid (HCl) as shown below:

MaVa /MbVb = nA/nB

Ma × 25 / 0.145 × 31.7 = 1

Cross multiply

Ma × 25 = 0.145 × 31.7

Ma × 25 = 4.5965

Divide both side by 25

Ma = 4.5965 / 25

Ma = 0.184 M

Therefore, the molarity of the acid (HCl) is 0.184 M

6 0

3 years ago