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gtnhenbr [62]
2 years ago
13

Which is equivalent to (4xy – 3z)2, and what type of special product is it?

Mathematics
2 answers:
Semmy [17]2 years ago
5 0
The last choice is right sure because this is a perfect square trinomial

(4xy -3z)^2 = 16x^2y^2 -24xyz +9z^2

hope this will help you 
KengaRu [80]2 years ago
3 0

Answer:

Option D is correct

16x^2y^2-24xyz+9z^2

a perfect square trinomial

Step-by-step explanation:

Using a perfect square trinomial:

(a-b)^2 = a^2-2ab+b^2          ....[1]

Given the expression:

(4xy-3z)^2

let a = 4xy and b = 3z

then;

Substitute in [1] we have

(4xy-3z)^2 = (4xy)^2-2(4xy)(3z)+(3z)^2

Simplify:

(4xy-3z)^2 =16x^2y^2-24xyz+9z^2

Therefore, the expression which is equivalent to (4xy-3z)^2 is 16x^2y^2-24xyz+9z^2 and type of special product is:  perfect square trinomial

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Arlecino [84]

Answer:4((x+3)(x-1))

Step-by-step explanation:

Factorize the common terms

4(x^2+2x-3)

Factorize

X^2+2x-3=(x+3)(x-1)

(X+3)(x-1)

4((x+3)(x-1))

3 0
3 years ago
Read the following prompt and type your response in the space provided.
Maslowich

Answer:

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Step-by-step explanation:

8 0
2 years ago
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Masja [62]

Answer:

Solving the expression \frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2) we get 6

The answer is 6.

Step-by-step explanation:

We need to find value of expression: \frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)

We know that \sqrt{81}=9

Our expression will become

\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{9 } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-2 -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-4)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4

We can write \sqrt[6]{8}=(2^3)^{\frac{1}{6}}=(2)^{\frac{3}{6}}=2^\frac{1}{2}=\sqrt{2}  \\

Now, replacing \sqrt[6]{8}=\sqrt{2}

=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4\\=\frac{2}{\sqrt{2} }.\sqrt{2}+4\\=2+4\\=6

So, solving the expression \frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2) we get 6

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Step-by-step explanation:

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