I believe your answer is C. But I’m not completely sure!
Answer:
*read explanation for both questions*
Step-by-step explanation:
So the first one asks <em>”the first number in a pattern is 6, the pattern follows the rule ’</em><em>multiply by 4’ </em><em>“</em>
The question has the answer to it, so each number would be multiplied by 4. So we have the first one which is 6, next we multiply 6 x 4 = 24. Then we multiply 24 x 4 = 96. and finally you multiply 96 x 4 = 384.
That’s the pattern fo the first one
The second one asks <em>“The shapes have been sorted into two groups. explain what attribute was used to sort the shapes.”</em>
<em />
When we’re looking for attributes, look for what they have in common. For me, I see that Group 1 has the smaller versions of the same shapes in Group 2. So that could be the attribute the question is asking for.
Based on the given question above, the correct answer would be the fourth option. The <span>circumstance that the cross section can be a non-rectangular parallelogram is that, </span><span>when the plane makes an acute angle to the base and intersects three vertical faces. Hope this answers the question. </span>
Answer:
![\left[\begin{array}{ccc}9\\10\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%5C%5C10%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Multiply the components of A by 3 then add corresponding components of
3a + b
3![\left[\begin{array}{ccc}2\\4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}3\\-2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}6\\12\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C12%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+
= ![\left[\begin{array}{ccc}6+3\\12-2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%2B3%5C%5C12-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
