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kolezko [41]
3 years ago
8

Find the other endpoint of the line segment with the given endpoint and mid point.

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0
So base on your question that ask to provide and end point of the four statement you give:
1.Endpoint(-1,9), midpoint:(-9,-10)  - (-17, -29)
2.Endpoint(2,5), midpoint(5,1) - (4,5)
3.Endpoint(9,-10), midpoint(4,8)  -  i cant determine sorry
4.Find the point that is one-fourth of the way from (2,4) to (10,8) - also i cant.
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A
blagie [28]

hope it helps.I was reading the same chapter

5 0
3 years ago
Which figure must be a square?
Rufina [12.5K]
A is describing either a rectangle, rhombus, or square, so that's not it. B is the same, C is also a possible rhombus, and so D is the correct answer as a square.
5 0
3 years ago
Read 2 more answers
Question 6 (1 point)
Alika [10]
59 cans ... she counting up by 5s so multiply 5 x 10
6 0
3 years ago
The pointer of the vibration measuring instrument is observed to move between the 0.1 and0.3 marks on the vertical scale, when s
Norma-Jean [14]

Answer:

Step-by-step explanation:

Given points moves b/w 0.1 of 0.3 marks Hence amplitude is 0.2

Also , frequency (w) = 100 rad/s.

Natural frequency (wn) = √K/m

K = 20 N/mm x 1000mm/1m = 20000N/M

W = 1000mm/1m = 20,000N/M

FormulaX = FolK/1 - (w/wn)²

0.2 = b/20000/1 - (100/50)²

Given forcing frequency was doubled, W1 = 2 x 100=200rad/s

X1 =b/20,000/1 - (200/20)²

0.2/11 = 1 - (200/50)²/1 - (100/50)² = 0.2/11 = -15^5– 3

X1 = 0.04

8 0
3 years ago
A group of five people are all working on the same mathematics problem. On the night before it is due, they call each other to d
UkoKoshka [18]

Answer:

Minimum number of calls = 10

Step-by-step explanation:

Lets name the five people as A,B,C,D and E.

<u>On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.</u>

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But  A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

                    = 10

5 0
3 years ago
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