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Kruka [31]
3 years ago
11

Find the 79th term of the following sequence 3,9,15,21

Mathematics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

237

Step-by-step explanation:

you just keep adding 3. so eventually you will get to 237, that will be the 79th term.   Hope this helps! :)

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QUADRATIC FORMULA SIMPLIFIED PLZ HELP
olga2289 [7]

Answer:

  • 3x² + 5x + 1 = 0 simplified
  • x = (-5 ± \sqrt{13})/6 roots

Step-by-step explanation:

<u>Given quadratic formula</u>

  • 3x² + 5x - 5 = - 6

<u>Standard form</u>

  • ax² + bx + c = 0

<u>Simplifying</u>

  • 3x² + 5x - 5 + 6 = 0
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<u>Solving</u>

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6 0
3 years ago
M. Score: 0 of 1 pt
beks73 [17]

Answer:

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Step-by-step explanation:

You can use divisibility rules to find the small prime factors.

The number ends in 5, so is divisible by 5.

  795/5 = 159

The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.

  159/3 = 53 . . . . . a prime number,* so we're done.

795 = 3×5×53

_____

* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.

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