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4 years ago

7

The French club is holding a car wash fundraiser. They are going to charge $20 per car, and expect between 30 and 100 cars. Iden

tify the independent and dependent quantity in the situation, and find reasonable domain and range values.

1 answer:

elixir [45]4 years ago

6 0

Answer:

They will make between 600 and 2000 dollars.

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Im in 8th grade yes this suvks

elena55 [62]

Answer:

:)

Step-by-step explanation:

its actually really good ur good at math it can get you to great schools nothing to be ashamed of!

3 0

3 years ago

Read 2 more answers

You were given the polynomial f(x)=3x^3+13x^2+19x+k and you know that f(-2)=0find k

eduard

Answer:

k = 10

Explanation:

The initial polynomial is:

$f(x)=3x^3+13x^2+19x+k$

If f(-2) = 0, then when we replace x by -2, the result will be 0. It means that we can write the following equation:

$\begin{gathered} f(-2)=3(-2)^3+13(-2)^2+19(-2)+k=0 \\ 3(-2)^3+13(-2)^2+19(-2)+k=0 \end{gathered}$

Therefore, we can solve for k as follows:

$\begin{gathered} 3(-8)+13(4)+19(-2)+k=0 \\ -24+52-38+k=0 \\ -10+k=0 \\ -10+k+10=0+10 \\ k=10 \end{gathered}$

So, the value of k is 10

6 0

1 year ago

Omar rides his unicycle on the playground.

Licemer1 [7]

Answer:

439.6 inches

Step-by-step explanation:

The distance apart cna be obtained using the formular :

Number of revolutions = 7

Diameter, d = 20 inches

π * number of revolutions * diameter

3.14 * 7 * 20

= 439.6 inches

6 0

3 years ago

Dati gli insiemi A(1,2,3,4,5) B(3,4,5,6,7) C(2,4,6,8) calcola il risultato della seguente espressione: (A∩B)∩C

Oduvanchick [21]

Answer:

(4)

Step-by-step explanation:

L'intersezione si occupa di elementi comuni

segno per intersezione = ∩

A = (1,2,3,4,5)

B = (3,4,5,6,7)

C = (2,4,6,8)

(A∩B)∩C

(A∩B) = (3, 4, 5)

(A∩B)∩C = (4)

6 0

3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago