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schepotkina [342]
2 years ago
10

Solutions of the equation: z2 - 12z + 36 = 0?

Mathematics
1 answer:
jasenka [17]2 years ago
7 0
36 becomes a negative 

First -36 + -1 -37
Next: -18 + -2 = -20 
Next: -12 + -3 = -15
Next: -9 + -4 which equals -13
Finally we get to the last part: -6 + -6 = -12

We change z2 to z^{2}

z^{2} - 6(z) = 36 

z(z) - 6

Because, we add up for the first two terms

Switch up, up the problem 6(z) - 6

Now, let's add the number 4 on the terms 
z - 6 (z - 6) 

Then, let's multiply z - 6 from z - 6 

z - 6^{2} = ? 


From this problem we have to add 6 from the sides that we are working with 

Therefore, your answer for z is 6 
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Ahat [919]

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A-3, B-4, C-1, D-2

Step-by-step explanation:

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2 years ago
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FrozenT [24]

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Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

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By SAS rule, ΔMNS ≅ ΔQNS.

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The correct option is MS and QS

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