Solutions of the equation: z2 - 12z + 36 = 0?
1 answer:
36 becomes a negative
First -36 + -1 -37
Next: -18 + -2 = -20
Next: -12 + -3 = -15
Next: -9 + -4 which equals -13
Finally we get to the last part: -6 + -6 = -12
We change z2 to
- 6(z) = 36
z(z) - 6
Because, we add up for the first two terms
Switch up, up the problem 6(z) - 6
Now, let's add the number 4 on the terms
z - 6 (z - 6)
Then, let's multiply z - 6 from z - 6
From this problem we have to add 6 from the sides that we are working with
Therefore, your answer for z is 6
First -36 + -1 -37
Next: -18 + -2 = -20
Next: -12 + -3 = -15
Next: -9 + -4 which equals -13
Finally we get to the last part: -6 + -6 = -12
We change z2 to
z(z) - 6
Because, we add up for the first two terms
Switch up, up the problem 6(z) - 6
Now, let's add the number 4 on the terms
z - 6 (z - 6)
Then, let's multiply z - 6 from z - 6
From this problem we have to add 6 from the sides that we are working with
Therefore, your answer for z is 6
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Solution : Third Option
Step-by-step explanation:
The first step here is to make all the signs uniform. As you can see the third inequality has a less than sign, which we can change to a greater than sign by dividing negative one on either side, making the inequality y > - 7.
Now take a look at the third option. Of course the y - coordinate, 3, is greater than - 7, so it meets the third requirement ( y > - 7 ). At the same time 3 > 1( 2 ) > 2, and hence it meets the second requirement as well. 3 > - 3( 1 ) + 4 > - 3 + 4 > 1, meeting the first requirement.
Therefore, the third option is a solution to the system.
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