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e-lub [12.9K]
3 years ago
14

A store had 235 MP3 players in the month of January. Every month, 30% of the MP3 players were sold and 50 new MP3 players were s

tocked in the store.
Which recursive function best represents the number of MP3 players in the store f(n) after n months?
a f(n) = 0.7 × f(n − 1) + 50, f(0) = 235, n > 0
b f(n) = 237 − 0.7 × f(n − 1) + 50, f(0) = 235, n > 0
c f(n) = 0.3 × f(n − 1) + 50, f(0) = 235, n > 0
d f(n) = 237 + 0.7 × f(n − 1) + 50, f(0) = 235, n > 0
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
The answer is A cause 30% is 0.7 and f(n-1) equals the amount being sold the +50 is for every 50 new one and the the 235 is for what they started with                                         
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\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
2 years ago
Read 2 more answers
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