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Sergeeva-Olga [200]
3 years ago
13

How high can you throw a rock if you can throw the ball 58.8 m/s straight up?​

Physics
1 answer:
NNADVOKAT [17]3 years ago
3 0

-- Gravity slows the ball by 9.8 m/s every second. So it slows to zero and reached its highest point in

(58.8 / 9.8) = 6 seconds .

-- Its average speed all the way up is

(1/2) (58.8 + 0) = 29.4 m/s

-- Traveling for 6 seconds at an average speed of 29.4 m/s, the ball covers

(6) (29.4) = 176.4 meters .

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Hope I was helpful

Explanation:

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State some important uses of magnet​
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Why would an egg break immediately when it hits the ground?
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How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?
Monica [59]

So, the work was done by that hot air-balloon is <u>30,000 J or 30 kJ</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. <u>Work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

\boxed{\sf{\bold{W = F \times s}}}

With the following condition :

  • W = work (J)
  • F = force (N)
  • s = shift or displacement (m)

Now, the s (displacement) can be written as ∆h (altitude change) because the object move to vertical line. The formula can also be changed to:

\boxed{\sf{\bold{W = F \times \Delta h}}}

With the following condition :

  • W = work (J)
  • F = force (N)
  • \sf{\Delta h} = change of altitude (m)

If an object has mass, then the object will also be affected by gravity. Always remember that F = m × g. So that :

\sf{W = F \times \Delta h}

\boxed{\sf{\bold{W = m \times g \times \Delta h}}}

With the following condition :

  • W = work (J)
  • m = mass of the object (kg)
  • g = acceleration of the gravity (m/s²)
  • \sf{\Delta h} = change of altitude (m)

<h3>Problem Solving</h3>

We know that :

  • F = force = 100 N
  • \sf{\Delta h} = change of altitude 300 m

What was asked :

  • W = work = ... J

Step by step :

\sf{W = F \times \Delta h}

\sf{W = 100 \times 300}

\boxed{\sf{W = 30,000 \: J = 30 \: kJ}}

<h3>Conclusion</h3>

So, the work was done by that hot air-balloon is 30,000 J or 30 kJ.

<h3>See More :</h3>
  • Work that he had done to lift object brainly.com/question/26341717
  • Converting work to potential energy brainly.com/question/26487284
5 0
3 years ago
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