Answer:
The hang time of a projectile can be calculated solely by knowing the vertical component of the velocity of projection
Explanation:
Answer:
1. S-S Repulsion N-S Attraction
2. S-N Attraction N-N Repulsion
Explanation:
1. S-S Repulsion N-S Attraction
2. S-N Attraction N-N Repulsion
250m good luck onnur test
Answer:
v = 1.7 m/s
Explanation:
Given that,
Initial velocity of the object, u = 1 m/s
Acceleration of the object, a = 1 m/s²
We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

So, the final velocity of the object is 1.7 m/s.
Answer:
Fg = 98.1 [N]; N = 98.1 [N]; Ff = 39.24 [N]; a = 2.076[m/^2]
Explanation:
To solve this problem, we must make a free body diagram and interpret each of the forces acting on the box. In the attached diagram we can find the free body diagram.
The gravitational force is equal to:
Fg = (10 * 9.81) = 98.1 [N]
Now by summing forces on the Y axis equal to zero, we can find the normal force exerted by the surface.
N - Fg = 0
N = Fg
N = 98.1 [N]
The friction force is defined as the product of normal force by the coefficient of friction.
Ff = N * μ
Ff = 98.1 * 0.4
Ff = 39.24 [N]
By the sum forces on the x-axis equal to the product of mass by acceleration (newton's second law), we can find the value of acceleration.
60 - Ff = m * a
60 - 39.24 = 10 * a
a = 2.076[m/^2]