Question

three players scored a total of 70 points during a basketball game one player scored twice as many as one mate and 10 points fewer than the other teammate. how many points did each player score

Answer 1

40+20+10=70
40 is twice 20
10 is 10 fewer than 20.

Answer 2

Answer:

24, 12 and 34.

Step-by-step explanation:

Let points of all three players are $x_1,\ x_2,\ x_3$ respectively.

It is given that sum of their score is 70.

Therefore, $x_1+x_2+x_3=70$. ...1

Also, score of one is twice the other.

So, $x_1=2x_2$.   ...2

It is also given that its score is 10 points less than the other one.

Therefore, $x_1=x_3-10$  ...3

Solving all three equations we get,

$x_1=24, \ x_2=12,\ x_3=34$.

Hence,it is the required solution.