Item 10 Find the median, first quartile, third quartile, and interquartile range of the data. 38,55,61,56,46,67,59,75,65,58
jok3333 [9.3K]
I think the median is 58.5, the first quartile is 50.5, the third quartile is 66, and finally, the interquartile range is <span>12.75.</span>
Answer:
75 is the length of the third side
I think the answer is 15x^4y^5z^2
Using simultaneous equation,
a=-1, b=1, x=1, y=0
OR
a=1, b=-1, x=1, y=0.
(x/5)-6=2
It depends by difference of. Difference between is more specific.
