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Semmy [17]
3 years ago
10

2log3(x) = 4 what is the solution?

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:

x = 2/log(3) is the solution

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Given that 3x-y : x+2y = 2 : 5, Determine the ratio x:y
N76 [4]

Answer:

x : y = 9 : 13

Step-by-step explanation:

Given that

3x - y : x + 2y = 2 : 5

Express the ratio in fractional form, that is

\frac{3x-y}{x+2y} = \frac{2}{5} ( cross- multiply )

5(3x - y) = 2(x + 2y) ← distribute parenthesis on both sides )

15x - 5y = 2x + 4y ( subtract 2x from both sides )

13x - 5y = 4y ( add 5y to both sides )

13x = 9y ( divide both sides by 13 )

x = \frac{9}{13} y ( divide both sides by y )

\frac{x}{y} = \frac{9}{13} , that is

x : y = 9 : 13

7 0
4 years ago
The volume of a rectangular prism is 5058 cubic inches.
astra-53 [7]

Answer:

412in

Step-by-step explanation:

5 0
3 years ago
Is the graph increasing or decreasing?<br> A:increasing <br> B:decreasing <br> C:constant
Ann [662]
Looks like the graph is decreasing to me
3 0
3 years ago
Five minutes on the clock
Nuetrik [128]

Answer:

15/32 cm²

Step-by-step explanation:

Area of rectangle = l × b

=> 3/4 × 5/8

=> 15/32

Therefore,

Area of rectangle is 15/32 cm²

4 0
3 years ago
Read 2 more answers
Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace
joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean \muand default \sigma, then the mean take seriously given as the straight line with a z score given by the confidence interval

\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\

Using formula:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z

the required probability: P(z>0.8349)=1-P(z

4 0
3 years ago
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