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slava [35]
3 years ago
7

PLEASEEEE HELP THANK YOU!!!

Mathematics
1 answer:
Temka [501]3 years ago
6 0

Answer:

- 4 < x ≤ 7

Step-by-step explanation:

Given

- 10 ≤ - 5x + 25 < 45 ( subtract 25 from all 3 intervals )

- 35 ≤ - 5x < 20

Divide all 3 intervals by - 5, reversing the inequality signs as a consequence.

7 ≥ x > - 4

Hence - 4 < x ≤ 7

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Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
What is the answer to this​
Gelneren [198K]

Answer:

the answer is d.

5 0
2 years ago
Write each number as a fraction or Mixed number.<br> (Please help! I'm trying to promote!)
aivan3 [116]

Answer:

0.7 repeating is 7/9

0.04 repeating is 4/99

4.45 repeating 4 4/11

2.19191919...... is 2 19/99

hope this helps

have a good day :)

Step-by-step explanation:

6 0
3 years ago
How do you solve 3^(4x) = 3^(5-x)?
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3^(4x) = 3^(5 - x)
4x = 5 - x
4x + x = 5
5x = 5
x = 5/5 = 1
x = 1
3 0
3 years ago
Which expression is equivalent to 3^8 times 3^7?
m_a_m_a [10]

Answer:

1/3⁵⁶ is the answer i think if it's not then i am sorry

5 0
2 years ago
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