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PtichkaEL [24]
3 years ago
14

What's the gcf of 64 and 48

Mathematics
1 answer:
Illusion [34]3 years ago
6 0
2 times 2 times 2 times 2= 16
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Help me ASAP please
Fofino [41]

Answer:

it is .42 how I know is because I looked at the graph

Step-by-step explanation:

first I look at the school side

next I look at the car and get rid of it because it says  middle school

then I get rid of bus and other

6 0
3 years ago
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A line passes through (6, 3), (8, 4), and (n, -2). Find the value of n.
timurjin [86]

Answer:

n = -4

Step-by-step explanation:

Notice how in the previous examples they all divide by 2? It is the same case here. So now the question is... "what" divided by "2" is "-2".

Let me show you:

n ÷ 2 = -2

if you know your integer math, you should know that...

-4 ÷2 = -2 (this is the correct equation)

8 0
1 year ago
45 times gives me a 100
GaryK [48]

Answer: what’s your question?

Step-by-step explanation:

7 0
3 years ago
What is angle hgf. If angle egf is 110 and angle hge is 3x+11 and angle hgf is 16x+4
Y_Kistochka [10]

Step-by-step explanation:

The Angle Addition Postulate de fusteer Key. Date ... 99° and MZLMF = 36º. Find m2LMN. 6) Find mZWDC if IZEDC = 145° and mZEDW= 61°. N of w. C ... 11) mZHGF = 16x + 4, m EGF = 110°,. 12) mZVUT = 175° ... a H, 16X+4=110 + 3x +11

7 0
3 years ago
the half life of polonium is 139 days. you have a brand new sample of polonium that will not be useful to you after 80% of the m
melamori03 [73]

The half-life of Po is 139 days, so its decay rate is

0.5 = e^(139k)  ==>  k = ln(0.5)/139

After some time t, 80% of the material will have decayed and you'll be left with a sample 20% of its original mass:

0.2 = e^(kt)  ==>  t = ln(0.2)/k = ln(0.2)/ln(0.5) * 139 = 322.748

so your sample is usable for about 323 days.

7 0
3 years ago
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