Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
A and D
Step-by-step explanation:
Answer:
it would be the Adjacent side (8) over the Hypotenuse, or the longest side which is 10. an easy way to remember this is CAH or Cosine=Adjacent/Hypotenuse
<em>x equals 22</em>
<h2>
Explanation:</h2>
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The Segment Postulate states the following:
<em>Given two end points A and B, a third point C lines on the segment AB if and only if the distances between the points satisfy the equation:</em>

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From the figure:

Our goal is to find x:

<h2>Learn more:</h2>
Dilation: brainly.com/question/2501119
#LearnWithBrainly
X is going to equal two in this equation.