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Naddik [55]
3 years ago
12

Match each subscript symbol to its correct meaning.

Chemistry
2 answers:
alisha [4.7K]3 years ago
7 0

Answer:

l=Liquid

g=Gas

aq=Aqueous solution

Explanation:

ad-work [718]3 years ago
5 0

Answer: (g) - gas, (l) - liquid and (aq) -  aqueous solution.

Explanation: The reactants are written in terms of their chemical formula on the left hand side of the arrow and the products are written in terms of their chemical formula on right hand side of the arrow.

The chemical symbols are followed by their physical states such as (l) for liquid, (s) for solid, (g) for gas and (aq) for aqueous.

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)



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If 00810 mol neon gas at the particular temperature and pressure occupies a volume of 214 mL ehat volume would 0.00684 mol neon
Grace [21]

Answer:

V_2=181mL

Explanation:

Hello,

In this case, Avogadro's relationship allows us to relate the moles and the volume of a gas at an initial condition and an a final one as shown below:

\frac{n_1}{V_1}=\frac{n_2}{V_2}

Thus, the volume that 0.00684 mol of neon the same pressure and temperature is computed below as required:

V_2=\frac{V_1*n_2}{n_1}=\frac{214mL*0.00684mol}{0.00810mol}  \\\\V_2=181mL

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6 0
3 years ago
The volume of a container is 40 cm3. It has a length of 4 cm, a width of 2 cm. What is the height of the container?
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4x2 =8, 8x5 =40
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Difference between modern and mendeleev's periodic table​
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Mendeleev’s was organized in atomic mass whereas the modern periodic table is organized by atomic number

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Assume that 50.0mL 50.0mL of 1.0MNaCl(aq) 1.0MNaCl(aq) and 50.0mL 50.0mL of 1.0M AgNO 3 (aq) 1.0MAgNO3(aq) were combined. Accord
S_A_V [24]

Answer:

The amount of precipitate formed would 7.175 grams of silver chloride.

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

Moles of NaCl = n

Volume of NaCl solution = 50.0 mL = 0.050 L

Molarity of the hydrogen peroxide = 2.0 M

n=2.0 M\times 0.050 L=0.100 mol

Moles of silver nitarte = n'

Volume of silver  nitrate solution = 50.0 mL = 0.050 L

Molarity of the silver nitrate = 1.0 M

n'=1.0 M\times 0.050 L=0.050 mol

NaCl(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NaNO_3(aq)

According to reaction, 1 mole of of silver nitrate reacts with 1 mole of NaCl. Then 0.050 mole of silve nitrate will :

\frac{1}{1}\times 0.050 mol=0.050 mol of NaCl

This means that silver nitrate is in limiting amount and NaCl is in excessive amount.

So, the amount of AgCl depends upon amount of silver nitrate.

According to reaction, 1 mole of silver nitrate gives 1 mole of AgCl.

Then 0.050 moles of silver nitrate will give;

\frac{1}{1}\times 0.050 mol=0.050 mol of AgCl

Mass of 0.050 moles of AgCl ;

0.050 mol\times 143.5 g/mol=7.175 g

The amount of precipitate formed would 7.175 grams of silver chloride.

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3 years ago
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The answer is starch

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