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aniked [119]
4 years ago
14

Please help me answer this question. -15 - g/3 = -5.What is g?​

Mathematics
2 answers:
olga2289 [7]4 years ago
4 0

Answer:

g = -30

Step-by-step explanation:

-15 - g/3 = -5

Add 15 to each side

-15+15 - g/3 = -5+15

-g/3=10

Multiply by -3 to each side

-g/3 * -3  = 10*-3

g = -30

Irina-Kira [14]4 years ago
3 0

Answer:

g= -30

Step-by-step explanation:

after writing down the problem, multiply both sides of the equation by 3 to get  -45-g= =15. then subtract 15 from both sides to get g=-30, which is your answer. hope this helps!

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3 years ago
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4 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
Please help me I don't understand!
Kobotan [32]
#3) since angle ABC is 115 degrees, to find EBC you simply have to subtract 115 from 90 and the answer is 25 degrees. 
#4)DGJ would be 30 degrees because you take 70 minus 40.
#5) a 90 degree angle. 
6 0
4 years ago
Read 2 more answers
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