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Inessa05 [86]
3 years ago
10

In a finance class, the final grade is based on three tests. Historically, the instructor tells the class that the joint probabi

lity of scoring "A"'s on the first two tests is 0.5. A student assigns a probability of 0.9 that she will get an "A" on the first test. What is the probability that the student will score an "A" on the second test given that she scored an "A" on the first test?
Mathematics
2 answers:
Liula [17]3 years ago
5 0

Answer:

The probability of getting an A on the second test given that she scored an A on the first test is P(A_1\&A_2)/P(A_1)=5/9\approx0.555.

Step-by-step explanation:

We assume that:

- The probability of getting A's in both exams is P=0.5.

- The probability of gettina an A in the first exam is P=0.9.

The probability of getting an A on the second test given that she scored an A on the first test can be calculated as:

P(A_1\&A_2)=P(A_1)*P(A_2|A_1)\\\\P(A_2|A_1)=P(A_1\&A_2)/P(A_1)=0.5/0.9=0.555

Brilliant_brown [7]3 years ago
3 0
D-- 0.44
P(A on the 2nd | A on the 1st) = P(A1 and A2)/P(A1) = .4/.9 = .44
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A Ferris wheel rotates 9π/8 radians prior to making a stop. The total height of the Ferris wheel is 246 ft. How far around did t
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Answer:

The ferris wheel travelled 434.717 ft.

Step-by-step explanation:

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2. A parking lot holds 40 cars. There are 20 cars in the lot already. Which inequality can be solved to show all the
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Solve the system of equations y=9x+13 y=2x+48
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7 0
4 years ago
The rectangular bar is connected to the support bracket with a 10-mm-diameter pin. The bar width is w = 70 mm and the bar thickn
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Answer:

P_max = 9.032 KN

Step-by-step explanation:

Given:

- Bar width and each side of bracket w = 70 mm

- Bar thickness and each side of bracket t = 20 mm

- Pin diameter d = 10 mm

- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa

- Average allowable shear stress of pin S = 115 MPa

Find:

The maximum force P that the structure can support.

Solution:

- Bearing Stress in bar:

                                       T = P / A

                                       P = T*A

                                       P = (120) * (0.07*0.02)

                                       P = 168 KN

- Shear stress in pin:

                                        S = P / A

                                        P = S*A

                                        P = (115)*pi*(0.01)^2 / 4

                                        P = 9.032 KN

- Bearing Stress in each bracket:

                                       T = P / 2*A

                                       P = T*A*2

                                       P = 2*(120) * (0.07*0.02)

                                       P = 336 KN

- The maximum force P that this structure can support:

                                      P_max = min (168 , 9.032 , 336)

                                      P_max = 9.032 KN

3 0
3 years ago
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