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3 years ago

(Q2) Determine the eccentricity, the type of conic, and the directrix for r = 9/1+cos theta

Mathematics

1 answer:

g100num [7]3 years ago

3 0

Answer:

The answer is (d) ⇒ eccentricity = 6 , hyperbola , directrix x = 3/2

Step-by-step explanation:

∵ r = ek/(1 ± ecosФ)

∵ r = 9/(1 + 6cosФ)

∴ e = 6 ⇒ eccentricity = 6

∵ e > 1

∴ The conic is hyperbola

∵ ek = 9

∴ k = 9/6 = 3/2

∴ The directrix x = 3/2

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Twenty-eight slices of pizza cost $12. Approximately how much would 70 slices cost?

Mademuasel [1]

Answer:

$30.

Step-by-step explanation:

70/28 = 2.5

12 x 2.5 = 30

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2 years ago

There are 156 sixth graders and 7 sixth grade teachers.There are 120 fifth graders and 5 fifth grade teachers.Which grade has lo

Katen [24]

Fifth grade has 24 students per each teacher.
Sixth grade has about 23 students per teacher.

Sixth grade is lower.

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3 years ago

Read 2 more answers

Find the value of x if DE is the midsegment of triangle ABC and

Varvara68 [4.7K]

Answer

Find out the value of x.

To prove

Definition of mid- segment

It is a segment connecting the midpoints of two sides of a triangle.

It is always parallel to the third side, and the length of the midsegment is half the length of the third side.

As shown in the triangle given below.

As given

DE = 5x and BC = 11x – 15

Thus

$DE = \frac{BC}{2}$

$5x = \frac{11x-15}{2}$

$5x\times 2 = 11x-15$

$10x = 11x-15$

15 = 11x - 10x

15 = x

Therefore the value of x is 15 .

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3 years ago

Factor 18x^3+24x^2-21x-28

maks197457 [2]

Hello my name is Jeff (sorry)

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3 years ago

FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli

____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0

1 year ago