3 years ago

(Q2) Determine the eccentricity, the type of conic, and the directrix for r = 9/1+cos theta

Mathematics

1 answer:

g100num [7]3 years ago

3 0

Answer:

The answer is (d) ⇒ eccentricity = 6 , hyperbola , directrix x = 3/2

Step-by-step explanation:

∵ r = ek/(1 ± ecosФ)

∵ r = 9/(1 + 6cosФ)

∴ e = 6 ⇒ eccentricity = 6

∵ e > 1

∴ The conic is hyperbola

∵ ek = 9

∴ k = 9/6 = 3/2

∴ The directrix x = 3/2

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