Ron has a bag containing 3 green pears and 4 red pears he randomly selects a lead then randomly selects another pear without rep

Question

muminat

3 years ago

10

Ron has a bag containing 3 green pears and 4 red pears he randomly selects a lead then randomly selects another pear without rep

lacement which three diagram shows the correct probabilities for this situation

Mathematics

1 answer:

Alborosie · Answer 1 · 2022-01-16T13:47:55+03:00

First pear    Second pear probability

green (3/7)---------green (2/6)    (3/7)*(2/6) = 1/7
      ---------red (4/6)    (3/7) *(4/6) = 2/7

red (4/7)-------------green (3/6) (4/7)*(3/6) = 2/7
   -------------red (3/6)    (4/7)*(3/6) = 2/7
   -------------------------
   1/7 + 2/7 + 2/7 + 2/7 = 1

The probailities that two are green are: 1/7

The probabilities that one is green and the other is red are:2 /7 + 2/7 = 4/7

The probabilities that two are red are: 2/7